macos - 为什么下面的汇编代码不打印出换行符(0xa)？

Question

在下面的代码中，NASM 按预期运行所有内容，除了在末尾打印新行字符。可能是什么原因？

%define sys_write       0x2000004           ; system call number for write
%define sys_read        0x2000003           ; system call number for read
%define sys_exit        0x2000001           ; system call number for exit
%define std_out         0x1                 ; file descriptor number for standard output
%define std_in          0x2                 ; file descriptor number for standard input
%define new_line        0xa                 ; a new line character
%define current_address $                   ; address of current location

; a macro to implement the write system call and write
; a string into standard output using two parameters
%macro write_string 2
    mov rax, sys_write                          ; system call to write
    mov rdi, std_out                            ; standard output
    mov rsi, %1                                 ; a string to write
    mov rdx, %2                                 ; length of the string
    syscall                                     ; kernel call interruption
%endmacro

; a macro to implement the exit system call
%macro exit 0
    mov rax, sys_exit                           ; system call to exit
    syscall
%endmacro

    section .data

message:    db 'Displaying 9 stars', new_line       ; a message
.length:    equ current_address - message           ; length of the message
asterisks:  times 9 db '*'                          ; a string of 9 asterisks

global start

    section .text

start:                                      ; linker entry point

    write_string message, message.length    ; print a message to standard output
    write_string asterisks, 9               ; print 9 asterisks
    write_string new_line, 1                ; print a line feed(new line)

    exit                                    ; end the program

组装后:

user$ nasm -f macho64 9stars.asm
user$ ld 9stars.o -o 9stars
ld: warning: -macosx_version_min not specified, assuming 10.10
user$ ./9stars

预期输出应该是:

Displaying 9 stars
*********
user$

但当前输出是:

Displaying 9 stars
*********user$

看起来 write_string new_line, 1 没有将 new_line 视为字符常量尽管在 db 'Displaying 9 star', new_line 中，new_line 添加了一个换行符，字符代码 10。我最初的猜测是 new_line 根本不是字符常量。这可能是什么原因？如何解决这个问题？我使用的是 Mac OS X 10.10。我有英特尔酷睿 i5 m540 CPU。我使用 NASM 版本 2.11.06。

Answer 1

write_string 需要字符串的地址，但 new_line 只是字符值 0xa 。尝试将其解释为字符串的地址将产生不可预测的结果。如果您想要一个仅包含可以打印的单个 0xa 的字符串，那么您需要执行如下操作:

    section .data

message:    db 'Displaying 9 stars', new_line       ; a message
.length:    equ current_address - message           ; length of the message
asterisks:  times 9 db '*'                          ; a string of 9 asterisks
newline:    db new_line                             ; <<< a single LF

global start

    section .text

start:                                      ; linker entry point

    write_string message, message.length    ; print a message to standard output
    write_string asterisks, 9               ; print 9 asterisks
    write_string newline, 1                 ; <<< print LF