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kotlin - 如何在 Kotlin 中将 actor 定义为一个类

转载 作者:行者123 更新时间:2023-12-02 04:23:57 28 4
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有个概念actor在 Kotlin 协程库中:

fun CoroutineScope.counterActor() = actor<CounterMsg> {
var counter = 0 // actor state
for (msg in channel) { // iterate over incoming messages
when (msg) {
is IncCounter -> counter++
is GetCounter -> msg.response.complete(counter)
}
}
}

文档说

A simple actor can be written as a function, but an actor with a complex state is better suited for a class.



什么是在 Kotlin 中定义为类的 Actor 的好例子?

最佳答案

class MyActor {
// your private state here
suspend fun onReceive(msg: MyMsg) {
// ... your code here ...
}
}

fun myActorJob(): ActorJob<MyMsg> = actor(CommonPool) {
with(MyActor()) {
for (msg in channel) onReceive(msg)
}
}

该示例取自 here .

关于kotlin - 如何在 Kotlin 中将 actor 定义为一个类,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/56644916/

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