java - 如何使用 ReplaceAll() 方法将整个字符串替换为空值？

Question

我想将此示例文件中的某个字符串替换为空值(空字符串)。我使用“\”来转义任何能让我的代码工作的东西。我只想替换此示例文件中的“TERMINAL: "UNKNOWN"”

示例文件:

SESSIONID: "19670" ENTRYID: "1" STATEMENT: "1" USERID: "%USERNAME%" USERHOST: "%SRCHOSTNAME%" ACTION: "100" RETURNCODE: "0"
SESSIONID: "19670" ENTRYID: "435" STATEMENT: "20" USERID: "%USERNAME%" USERHOST: "%SRCHOSTNAME%" TERMINAL: "UNKNOWN" ACTION: "3" RETURNCODE: "0" 
SESSIONID: "19670" ENTRYID: "1" STATEMENT: "1" USERID: "%USERNAME%" USERHOST: "%SRCHOSTNAME%" ACTION: "101" RETURNCODE: "0

预期输出:

SESSIONID: "19670" ENTRYID: "1" STATEMENT: "1" USERID: "%USERNAME%" USERHOST: "%SRCHOSTNAME%" ACTION: "100" RETURNCODE: "0"
SESSIONID: "19670" ENTRYID: "435" STATEMENT: "20" USERID: "%USERNAME%" USERHOST: "%SRCHOSTNAME%" ACTION: "3" RETURNCODE: "0" 
SESSIONID: "19670" ENTRYID: "1" STATEMENT: "1" USERID: "%USERNAME%" USERHOST: "%SRCHOSTNAME%" ACTION: "101" RETURNCODE: "0

我的代码:

public static void main(String[] args) throws FileNotFoundException {
    Scanner scan = new Scanner(new File("oracle.log"));
    ArrayList<String> list = new ArrayList<String>();
    while (scan.hasNext()) {
        list.add(scan.next());
    }
    scan.close();

    try {
        //initiates a new File type file
        File file = new File("oracle.log");
        //initiates a new buffereed reader "reader"
        BufferedReader reader = new BufferedReader(new FileReader(file));
        //initialize 2 strings for comparison
        String line = "", oldtext = "";
        while ((line = reader.readLine()) != null) {
            oldtext += line + "\r\n";
        }
        reader.close();

        oldtext = oldtext.replaceAll("%TERMINAL: \"UNKNOWN\"", "");
        FileWriter writer = new FileWriter("new_oracle.log");

        // the entire file is contained within the String 'oldtext'
        writer.write(oldtext);
        writer.close();
    } catch (IOException ioe) {
        ioe.printStackTrace();
    }

}

输出:相同的示例文件，没有任何更改

Answer 1

(基于我的评论)正则表达式中的 % 字符与文字“%”符号匹配。我不确定您想在那里做什么，但请尝试将其删除。

我知道在某些情况下 % 用于匹配任何内容，在这种情况下您可以在正则表达式中使用 .*，但这会删除队列中的所有内容直到比赛结束。

终端:\“未知\”

我在 regex101 上测试了它，它工作正常(该工具不需要转义引号，但对于 java 则需要转义)https://regex101.com/r/eB2yW9/1