python - python Hackerrank 中的 EOF 错误

Question

尝试解决问题，但 Hackerrank 的编译器在解析时不断抛出错误 EOFError:不知道哪里错了。

#!usr/bin/python

b=[]
b=raw_input().split()
c=[]
d=[]
a=raw_input()
c=a.split()
f=b[1]
l=int(b[1])
if(len(c)==int(b[0])):          
    for i in range(l,len(c)):
        d.append(c[i])
        #print c[i]
    for i in range(int(f)):
        d.append(c[i])
        #print c[i]
for j in range(len(d)):
    print d[j],

我也尝试过 try catch 来解决它，但没有得到任何输入。

try:
    a=input()
    c=a.split()
except(EOFError):
    a=""

输入格式是开头为 2 个空格的整数，然后是数组

回溯错误是:

Traceback (most recent call last):
  File "solution.py", line 4, in <module>
    b=raw_input().split()
EOFError: EOF when reading a line

Answer 1

有多种方法可以处理 EOF 错误。

1.抛出异常:

while True:
  try:
    value = raw_input()
    do_stuff(value) # next line was found 
  except (EOFError):
    break #end of file reached

2.检查输入内容:

while True:
  value = raw_input()
  if (value != ""):
    do_stuff(value) # next line was found 
  else:
    break 

3.使用 sys.stdin.readlines() 将它们转换为列表，然后使用 for-each 循环。更详细的解释是Why does standard input() cause an EOF error

import sys 

# Read input and assemble Phone Book
n = int(input())
phoneBook = {}
for i in range(n):
    contact = input().split(' ')
    phoneBook[contact[0]] = contact[1]

# Process Queries
lines = sys.stdin.readlines()  # convert lines to list
for i in lines:
    name = i.strip()
    if name in phoneBook:
        print(name + '=' + str( phoneBook[name] ))
    else:
        print('Not found')