java - java 猜数字游戏

Question

我正在编写一个java代码，要求用户猜测计算机的随机数，我已经很好了，但是，我想做的是一条与用户猜测的次数相对应的消息。

例如，如果用户在 1 次尝试中猜中了随机数，则会输出“Excellent!”如果用户猜到了 2-4 中的答案，请尝试“干得好”等等。

我想我还没有尝试过任何东西，因为我不确定将代码粘贴在哪里？
我知道必须是 ifguess == 1 then do this else if code >1<=3 then do this 等等..但是在我的代码中？它也应该在带有嵌套 if 的 while 循环中吗？

这是我更新的代码，它按照我创建它所需的确切方式运行和编译。感谢您的帮助!

public static void main(String[] args) {
        Random rand = new Random();
        int compNum = rand.nextInt(100);
        int count = 0;
        Scanner keyboard = new Scanner(System.in);
        int userGuess;  
        boolean win = false;        
        while (win == false ){
            System.out.print("Enter a guess between 1 and 100: ");
            userGuess = keyboard.nextInt();
            count++;
            if(userGuess < 1 || userGuess > 100){
                System.out.println("Your guess is out of range.  Pick a number between 1 and 100.");
                System.out.println();
            }
            else if (userGuess == compNum){
                win = true;
                System.out.println("Congratulations!  Your answer was correct! ");
            }       
            else if (userGuess < compNum){
                System.out.println("Your guess was too low.  Try again. ");
                System.out.println();
            }
            else if (userGuess > compNum){
                System.out.println("Your guess was too high.  Try again. ");
                System.out.println();
            }

        }
        if(count == 1){
            System.out.println();
            System.out.println("I had chosen " + compNum + " as the target number.");
            System.out.println("You guessed it in " + count + " tries.");
            System.out.println("That was lucky!");
        }
        else if (count > 1 && count <= 4){
            System.out.println();
            System.out.println("I had chosen " + compNum + " as the target number.");
            System.out.println("You guessed it in " + count + " tries.");
            System.out.println("That was amazing!");
        }
        else if (count > 4 && count <= 6){
            System.out.println();
            System.out.println("I had chosen " + compNum + " as the target number.");
            System.out.println("You guessed it in " + count + " tries.");
            System.out.println("That was good.");
        }
        else if (count > 6 && count <= 7){
            System.out.println();
            System.out.println("I had chosen " + compNum + " as the target number.");
            System.out.println("You guessed it in " + count + " tries.");
            System.out.println("That was OK.");
        }               
        else if (count > 7 && count <= 9){
            System.out.println();
            System.out.println("I had chosen " + compNum + " as the target number.");
            System.out.println("You guessed it in " + count + " tries.");
            System.out.println("That was not very good.");
        }
        else if (count > 10){
            System.out.println();
            System.out.println("I had chosen " + compNum + " as the target number.");
            System.out.println("You guessed it in " + count + " tries.");
            System.out.println("This just isn't your game.");

        }
    }
        }

Answer 1

您可以计算迭代次数。类似的东西。

boolean notCorrect = true;
int guesses = 0;
while(notCorrect){
    //Code for checking user input. 
    //break out if true
    guesses++;
}

抱歉，搞反了。

其他地方

if(guesses < 2) {
    // display message
}
// include other if's to determine which message to display.

您可以将决定显示哪条消息的 if 语句放在检查猜测是否正确的 if 语句中。但把它从循环中拉出来。这样，如果用户确实猜对了，您就只能运行该代码。

if (userGuess == compNum){
    win = true;
    System.out.println("Congratulations! Your answer was correct! ");
    // put message decision here...
}