java - 使用startsWith() 搜索数组

Question

我正在寻找一些使用startsWith()在数组中搜索的帮助。

我希望用户输入名字，搜索数组，如果名字匹配，则打印:员工 ID 号、姓氏、名字。

如果没有匹配项，则返回一条简单的错误消息。

下面的代码搜索数组，打印匹配的员工，但也继续打印错误消息，直到循环整个数组。

当前输出:

ID No: 2345 - Holt, Steve
ID No: 2345 - Molt, Steve
ID No: 2345 - Sholt, Steve
ID No: 2345 - Colt, Steve
No Matching employee records found!
No Matching employee records found!
No Matching employee records found!
No Matching employee records found!
...

如何将其更改为仅返回匹配项，或者如果不匹配，则仅返回错误消息。

感谢您的帮助!

private static final Service [] employeeList = new Employee [10];
private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args){

                                    // First name / Last name / Employee Number

  final Employee FakeEmployee0 = new Employee("Steve", "Holt", "2345");
  final Employee FakeEmployee1 = new Employee("Steve", "Molt", "2111");
  final Employee FakeEmployee2 = new Employee("Steve", "Sholt", "245");
  final Employee FakeEmployee3 = new Employee("Steve", "Colt", "2222");
  final Employee FakeEmployee4 = new Employee("Steve", "Wolt", "25");
  final Employee FakeEmployee5 = new Employee("Boy", "Blue", "1");
  final Employee FakeEmployee6 = new Employee("Boy", "Wonder", "8999");
  final Employee FakeEmployee7 = new Employee("Boy", "George", "500");
  final Employee FakeEmployee8 = new Employee("Will", "Smith", "123");
  final Employee FakeEmployee9 = new Employee("Will", "Ferret", "23");      

  employeeList [0] = FakeEmployee0;
  employeeList [1] = FakeEmployee1;
  employeeList [2] = FakeEmployee2;
  employeeList [3] = FakeEmployee3;
  employeeList [4] = FakeEmployee4;
  employeeList [5] = FakeEmployee5;
  employeeList [6] = FakeEmployee6;
  employeeList [7] = FakeEmployee7;
  employeeList [8] = FakeEmployee8;
  employeeList [9] = FakeEmployee9;

// Search for employees by first name:

  private static void searchNames(){

    System.out.println("Enter employee's first name: ");
    String nameCheck = sc.nextLine();


    for (int i = 0; i < employeeList.length; i++){
        if (employeeList[i].getFirstName().startsWith(nameCheck)){
            System.out.println("ID No: " + employeeList[i].getIdNum() + " - "
                               + employeeList[i].getLastName() + " " +
                               employeeList[i].getFirstName());
        }

        else {
            System.out.println("No Matching employee records found!");
        }
}
}

Answer 1

问题出现在您的for循环中。您实际上是在为每个员工打印与您的描述不符的错误消息。

要解决这个问题，您可以简单地使用一个 boolean 标志，调用empFound，它最初设置为false。当您检查员工时，如果找到匹配项，则只需将 empFound 设置为 true 并打破循环即可。

在 for 循环之外，当且仅当 empFound 为 false 时才显示错误消息。

正如 @vvs 所指出的，一旦您找到匹配项，此处提出的解决方案就会停止，也就是说，它最多会产生 1 个命中。如果您想列出以您所在字符串开头的所有员工，只需省略 break 语句即可。这将导致循环继续进行并检查所有员工元素。