java - 无法生成一排敌人，仅生成一个敌人 :\

Question

Controller 类:

 package com.game.src.main;

    import java.awt.Graphics;
    import java.util.LinkedList;
    import java.util.Random;

    public class Controller 
    {
        private LinkedList<Enemy> e = new LinkedList<Enemy>();

        Random r = new Random();

        Enemy TempEnemy = null;

        Game game;
        Textures tex;

        public Controller(Game game, Textures tex)
        {
            this.game = game;
            this.tex = tex;

            **for(int x = 0; x < (Game.WIDTH * Game.SCALE); x += 21)
                addEnemy(new Enemy(x, 200, tex));**
        }

        public void tick()
        {
            for(int i = 0; i < e.size(); i++)
                TempEnemy = e.get(i);

            TempEnemy.tick();
        }

        public void render(Graphics g)
        {
            for(int i = 0; i < e.size(); i++)
                TempEnemy = e.get(i);

                TempEnemy.render(g);
        }

        public void addEnemy(Enemy block)
        {
            e.add(block);
        }

        public void removeEnemy(Enemy block)
        {
            e.remove(block);
        }
    }

我的构造函数中的 for-Loop 没有创建一行敌人。它应该做的是渲染一排敌人 Sprite ，但它会渲染屏幕最右角的最后一个。 :\敌人等级如下:

package com.game.src.main;

import java.awt.Graphics;

public class Enemy 
{
    private int x = 0;
    private int y = 0;
    private Textures tex = null;

    public Enemy(int x, int y, Textures tex)
    {
        this.x = x;
        this.y = y;
        this.tex = tex;
    }

    public void tick()
    {
        y+= 3;
        if(y >= (Game.HEIGHT * Game.SCALE))
            y = 0;
    }

    public void render(Graphics g)
    {
        g.drawImage(tex.spike, x, y, null);
    }
}

纹理类别:

    package com.game.src.main;

import java.awt.image.BufferedImage;

public class Textures 
{
    public BufferedImage player, spike;

    private SpriteSheet ss;

    public Textures(Game game)
    {
        ss = new SpriteSheet(game.getSpriteSheet());
        getTextures();
    }

    private void getTextures()
    {
        player = ss.grabImage(1, 1, 44, 65);
        spike = ss.grabImage(1, 3, 21, 65);

    }

    public void setUp()
    {
        player = ss.grabImage(3, 1, 43, 65);
    }

    public void setDown()
    {
        player = ss.grabImage(1, 1, 43, 65);
    }

    public void setLeft()
    {
        player = ss.grabImage(5, 1, 43, 65);
    }

    public void setRight()
    {
        player = ss.grabImage(7, 1, 43, 65);
    }
}

Answer 1

括号!

改变这个

    public void render(Graphics g)
    {
        for(int i = 0; i < e.size(); i++)
            TempEnemy = e.get(i);

            TempEnemy.render(g);
    }

到此

    public void render(Graphics g)
    {
        for(int i = 0; i < e.size(); i++){
            TempEnemy = e.get(i);
            TempEnemy.render(g);
        }
    }

PS:即使您只需要执行一行，也请始终为循环、if 语句等编写括号。你可以避免这种挣扎。

<小时/>

此外，您不需要“TempEnemy”，此代码的作用相同:

    public void render(Graphics g)
    {
        for(int i = 0; i < e.size(); i++){
            e.get(i).render(g);
        }
    }