java - 由于If语句无法登录

Question

我想登录系统。当使用 ID 和帐号创建客户时，我尝试输入它们，并希望如果 ID 和帐户已连接 - 对话框将打开。

当我创建客户 ID 时，在构造函数中我将其转换为字符串:

Customer(int id, String pps, String name, String surname, String birthday, String password){

        this.id = nextId.incrementAndGet();
        Integer.toString(this.id);  

当我在另一个类中创建帐户时，但对于客户，我在构造函数中执行了相同的操作(我将帐号转换为字符串):

public CustomerAccount(int accountNumber, double balance){

        Random n = new Random();
        this.accountNumber = 100000 + n.nextInt(900000);
        Integer.toString(this.accountNumber);

在我的驱动程序类中，我有按钮，然后，当我按下按钮时，对话框应该打开。

depositW.addActionListener(new ActionListener() {

                public void actionPerformed(ActionEvent e) {
                     JFrame frame = new JFrame(" ");
                     boolean found1 = false;
                     boolean found = false;


                     String a = JOptionPane.showInputDialog("Please enter the ID number: ");         
                     for(Customer aCustomer: customers){
                         System.out.println("ID: " + a + " = " + aCustomer.getId());
                         if(a.equals(aCustomer.getId())){
                             BankInterface.setCurrentCustomer(aCustomer);
                             found1 = true;
                         }else{
                  JOptionPane.showMessageDialog(frame, "There is no customer with this ID number", "Please try again", JOptionPane.WARNING_MESSAGE);
                       }

                if(found1){      
                     String b = JOptionPane.showInputDialog("Please enter the account number: ");   
                               for(CustomerAccount cu: BankInterface.getCurrentCustomer().getAccounts()){ 
                                   System.out.println("Account: " + a + " = " + cu.getAccountNumber());
                                   if(b.equals(cu.getAccountNumber())){

                                      BankInterface.setCurrentAccount(cu);
                                      found = true;
                                   }
                                }
                }

                if(found && found1){
                     new WithdrawDepositDialog(BankInterface.this, customers);
                }else{
                    JOptionPane.showMessageDialog(frame, "The username or password is not correct", "Please try again", JOptionPane.WARNING_MESSAGE);
                }
                  }
                    }
            }); 

当我测试它时，在我的控制台窗口中出现以下内容:所以它在运行时找不到 id。

ID: 1 = 1
ID: 1 = 2

我现在确定了，问题出在哪里。我猜我的 if 语句中有什么问题。这个问题可能的解决方案是什么？

<小时/>

更新的代码:

String a = JOptionPane.showInputDialog("Please enter the ID number: ");
for (Customer aCustomer: customers) {
    System.out.println("ID: " + a + " = " + aCustomer.getId());
    if (a.equals(aCustomer.getId())) {
        BankInterface.setCurrentCustomer(aCustomer);
        found1 = true;
        break;
    }
}
if (!found1) {
    JOptionPane.showMessageDialog(frame, "There is no customer with this ID number", "Please try again", JOptionPane.WARNING_MESSAGE);
}

Answer 1

代码运行得很好。

您对所有客户的循环:

for(Customer aCustomer: customers){

不在此终止:

if(a.equals(aCustomer.getId())){
     BankInterface.setCurrentCustomer(aCustomer);
      found1 = true;
}

因为found1 = true不是循环条件。您在这里缺少的是在该行之后的一个简单的 break; 。