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java - 选择查询星期几?

转载 作者:行者123 更新时间:2023-12-02 03:58:20 25 4
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我有事件表,其中包含开始时间、结束时间、星期几、位置等。我想根据星期几检索记录。我将 dayOfWeek 保存为字符串。(“周一”、“周二”等)。

如何检索每天的记录?

这是我的 EventTableHelper。

public class EventTableHelper extends SQLiteOpenHelper {


private static final String TABLE = "event";
private static final String KEY_ID = "id";
private static final String KEY_TITLE = "title";
private static final String KEY_FROM_DATE = "datefrom";
private static final String KEY_TO_DATE = "dateto";
private static final String KEY_DAY_OF_WEEK = "dayofweek";
private static final String KEY_LOCATION = "location";
private static final String KEY_NOTIFICATION_TIME = "notification";


public EventTableHelper(Context context) {
super(context, Constants.DATABASE_NAME, null, Constants.DATABASE_VERSION);

}

@Override
public void onCreate(SQLiteDatabase db) {
}

public void createTable(SQLiteDatabase db){
String CREATE_EVENTS_TABLE = "CREATE TABLE " + TABLE+ "("
+ KEY_ID + " INTEGER PRIMARY KEY,"
+ KEY_TITLE + " TEXT,"
+ KEY_FROM_DATE + " DATE,"
+ KEY_TO_DATE + " DATE,"
+ KEY_DAY_OF_WEEK + " TEXT,"
+ KEY_LOCATION + " TEXT,"
+ KEY_NOTIFICATION_TIME + "TEXT" + ")";
db.execSQL(CREATE_EVENTS_TABLE);
}
// Upgrading database
@Override
public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) {

db.execSQL("DROP TABLE IF EXISTS " + TABLE);

// createTable(db);
// onCreate(db);
}

public void addEvent(EventData event) {
SQLiteDatabase db = this.getWritableDatabase();

ContentValues values = new ContentValues();
values.put(KEY_TITLE,event.getTitle());
values.put(KEY_FROM_DATE, event.getFromDate());
values.put(KEY_TO_DATE,event.getToDate());
values.put(KEY_DAY_OF_WEEK,event.getDayOfWeek());
values.put(KEY_LOCATION,event.getLocation());
values.put(KEY_NOTIFICATION_TIME,event.getNotificationTime());

db.insert(TABLE, null, values);

db.close();
}

EventData getEvent(int id) {

SQLiteDatabase db = this.getReadableDatabase();
EventData eventData = new EventData();
Cursor cursor = db.query(TABLE, new String[]{KEY_ID,
KEY_TITLE, KEY_FROM_DATE, KEY_TO_DATE, KEY_DAY_OF_WEEK, KEY_LOCATION}, KEY_ID + "=?",
new String[]{String.valueOf(id)}, null, null, null, null);

if( cursor != null && cursor.moveToFirst() ) {
eventData = new EventData(Integer.parseInt(cursor.getString(0)), cursor.getString(1), cursor.getString(2),
cursor.getString(3), cursor.getString(4), cursor.getString(5),cursor.getString(6));

}
return eventData;
}

public List<EventData> getAllEvents() {
List<EventData> conList = new ArrayList<EventData>();

String selectQuery = "SELECT * FROM " + TABLE ;

SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);

if (cursor.moveToFirst()) {
do {

EventData event = new EventData();

event.setId(Integer.parseInt(cursor.getString(0)));
event.setTitle(cursor.getString(1));
event.setFromDate(cursor.getString(2));
event.setToDate(cursor.getString(3));
event.setDayOfWeek(cursor.getString(4));
event.setLocation(cursor.getString(5));
event.setNotificationTime(cursor.getString(6));

conList.add(event);
} while (cursor.moveToNext());
}

return conList;
}



public int updateEvent(EventData event) {
SQLiteDatabase db = this.getWritableDatabase();

ContentValues values = new ContentValues();
values.put(KEY_TITLE,event.getTitle());
values.put(KEY_FROM_DATE,event.getFromDate());
values.put(KEY_TO_DATE,event.getToDate());
values.put(KEY_DAY_OF_WEEK,event.getDayOfWeek());
values.put(KEY_LOCATION,event.getLocation());
values.put(KEY_NOTIFICATION_TIME,event.getNotificationTime());


// updating row
return db.update(TABLE, values, KEY_ID + " = ?",
new String[] { String.valueOf(event.getId()) });
}
public void deleteEvent(EventData eventData) {
SQLiteDatabase db = this.getWritableDatabase();
db.delete(TABLE, KEY_ID + " = ?",
new String[]{String.valueOf(eventData.getId())});
db.close();
}

}

我尝试像这样检索:

   public List<EventData> getAllEvents(String day) {
List<EventData> conList = new ArrayList<EventData>();

String selectQuery = "SELECT * FROM " + TABLE + " WHERE (" + KEY_DAY_OF_WEEK + " = " + day;

SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);

if (cursor.moveToFirst()) {
do {

EventData event = new EventData();

event.setId(Integer.parseInt(cursor.getString(0)));
event.setTitle(cursor.getString(1));
event.setFromDate(cursor.getString(2));
event.setToDate(cursor.getString(3));
event.setDayOfWeek(cursor.getString(4));
event.setLocation(cursor.getString(5));
event.setNotificationTime(cursor.getString(6));

conList.add(event);
} while (cursor.moveToNext());
}

return conList;
}

但它给出了语法错误:

 android.database.sqlite.SQLiteException: near "Mon": syntax error (code 1): , while compiling: SELECT  * FROM event WHERE (dayofweek = Mon)

我正在检索这样的事件:

String day = "Mon"
mDb = new EventTableHelper(getActivity());
events = mDb.getAllEvents(day);

我正在另一个 Activity 中保存 dayOfWeek。我想检索 fragment 中的记录。我不知道如何在函数中传递日期参数。

最佳答案

喜欢在单引号中传递值

String selectQuery = "SELECT  * FROM " + TABLE + " WHERE " + KEY_DAY_OF_WEEK +" = '"+day+ "'";

关于java - 选择查询星期几?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35194433/

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