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java - 返回错误的值,但在系统中读取正常? java

转载 作者:行者123 更新时间:2023-12-02 03:55:38 25 4
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我正在尝试读取此输入:

processcount 2     # Read 2 processes
runfor 15 # Run for 15 time units
use rr # Can be fcfs, sjf, or rr
quantum 2 # Time quantum – only if using rr
process name P1 arrival 3 burst 5
process name P2 arrival 0 burst 9
end

我的工作是只解析值而不解析单词,并保留注释 (#)。

这是主文件:

public class main {

static String[] token = new String[10];
static List<Schedule> p;

public static void schedule()
{
for(Schedule c: p)
{
System.out.println("ProcessInfo: " + c.getProcess().processName);
System.out.println("count: " + c.getProcessCount());
System.out.println("quant: " + c.getQuantum());
System.out.println("runtime: " + c.getRunTime());
System.out.println("Type: " + c.getType());
}
}


public static void main(String[] args) throws Exception {
Scanner sc = new Scanner(System.in);
// sc = new Scanner(new File("processes.in"));
p = new ArrayList<>();

while(sc.hasNextLine() && !sc.equals("end"))
{

token = sc.nextLine().replace(" ","-").replace("#", "-").split("-");

System.out.println(token[0].toString());


if(!token[0].startsWith("#") || !sc.nextLine().startsWith("end"))
{
Schedule s = new Schedule();
int pCount=0, runfor=0, quantum=0, arrival=0, burst=0;
String type = null, pName = null;

if(token[0].startsWith("processcount"))
{
s.setProcessCount(Integer.parseInt(token[1]));
System.out.println(Integer.parseInt(token[1] +""));
}


else if(token[0].startsWith("runfor"))
{
s.setRunTime(Integer.valueOf(token[1].toString()));
System.out.println(Integer.parseInt(token[1]) +"");
}

else if(token[0].startsWith("use"))
{
s.setType(token[1].toString());
System.out.println(token[1] +"");
}

else if(token[0].startsWith("quantum"))
{
s.setQuantum(Integer.valueOf(token[1].toString()));
System.out.println(token[1] + "");
}

else if(token[0].startsWith("process"))
{
Processes pl = new Processes();
pl.setProcessName(token[2]);
System.out.println(token[2]+ "");

pl.setArrivalTime(Integer.valueOf(token[4].toString()));
System.out.println(""+ Integer.valueOf(token[4]));

pl.setBurstTime(Integer.valueOf(token[6].toString()));
System.out.println("" + token[6]);

s.setProcess(pl);
// add info
p.add(s);

}

else if(token[0].startsWith("end"))
{
schedule();
}

}

}

}

}

这是时间表:

public class Schedule { 

int processCount;
int runTime;
String type;
int quantum;
Processes process;


public int getProcessCount() {
return processCount;
}

public void setProcessCount(int processCount) {
this.processCount = processCount;
}

public int getRunTime() {
return runTime;
}

public void setRunTime(int runTime) {
this.runTime = runTime;
}

public String getType() {
return type;
}

public void setType(String type) {
this.type = type;
}

public int getQuantum() {
return quantum;
}

public void setQuantum(int quantum) {
this.quantum = quantum;
}

public Processes getProcess() {
return process;
}

public void setProcess(Processes p) {
process = p;
}
}

流程如下:

public class Processes {

String processName;
int arrivalTime;
int burstTime;

public String getProcessName() {
return processName;
}

public void setProcessName(String processName) {
this.processName = processName;
}
public int getArrivalTime() {
return arrivalTime;
}

public void setArrivalTime(int arrivalTime) {
this.arrivalTime = arrivalTime;
}

public int getBurstTime() {
return burstTime;
}

public void setBurstTime(int burstTime) {
this.burstTime = burstTime;
}
}

这是我用代码得到的输出:

ProcessInfo: P1
count: 0
quant: 0
runtime: 0
Type: null
ProcessInfo: P2
count: 0
quant: 0
runtime: 0
Type: null

为什么我返回的结果是错误的?

最佳答案

这里有几个问题。您在 while 循环的每次迭代中创建一个新的计划;在新的迭代之前,您不会获得当前行的所有相关值,而且在创建新的 Schedule() 后,您还会有几个无用的变量,这些变量会覆盖以前收集的值。另外,您在数组的 String 元素上使用 toString ,这是没有意义的。就我个人而言,我不会尝试不使用过滤器,而且您实际上并不需要任何过滤器。始终尝试KISS (保持简单愚蠢)

以下是我将如何在不使用过滤器的情况下进行操作。

public static void main (String args [])
{
// Will help us identify the key words
String current_token;

Scanner sc = new Scanner(System.in);

String input = sc.nextLine();
//Remove spaces at the beginning and end of the string
input = input.trim();

Schedule s = new Schedule();

// New source for the scanner
sc =new Scanner(input);

p = new ArrayList<>();

while(sc.hasNext())
{
current_token = sc.next();

if(current_token.equals("end"))
{schedule(); break;}

switch(current_token)
{
case "processcount":
s.setProcessCount(sc.nextInt());
System.out.println(s.getProcessCount()+ " ");
break;

case "runfor":
s.setRunTime(sc.nextInt());
System.out.println(s.getRuntime +" ");

case "use":
s.setType(sc.next());
System.out.println(s.getType() +" ");
break;

case "quantum":
s.setQuantum(sc.nextInt());
System.out.println(s.getQuantum + " ");
break;

case "process":
Processes pl = new Processes();

pl.setProcessName(sc.next());
System.out.println(pl.GetProcessName()+ " ");

pl.setArrivalTime(sc.nextInt());
System.out.println(" "+ pl.getArrivalTime());

pl.setBurstTime(sc.nextInt());
System.out.println(" " + pl.getBurstTime());

s.setProcess(pl);
// add info
p.add(s);

break;

default:
// the current_token is not what we are looking for
break;
}
}
}

关于java - 返回错误的值,但在系统中读取正常? java ,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/35496696/

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