python - 单击菜单并打开新窗口

Question

我使用 Qt 设计器创建了两个不同的窗口，input_window.ui 和 help_window.ui。这是用于显示输入窗口的 python 脚本。在输入窗口中，有一个菜单栏(“关于>>帮助”)。点击“Help”时怎么会弹出help_window？

Here is init.py

import sys
from input_window import Ui_MainWindow
from PyQt5.QtWidgets import QMainWindow, QApplication
from help_window import Ui_Help



class MainWindow(QMainWindow, Ui_MainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)
        self.setupUi(self)
        self.Pophelp.triggered.connect(self.Ui_Help)


    def help_window(self):
        self.window=Ui_Help()
        self.window.show()

if __name__ == "__main__":
    app = QApplication(sys.argv)
    window = MainWindow()
    window.show()
    sys.exit(app.exec_())

这是Ui_Help的代码

from PyQt5 import QtCore, QtGui, QtWidgets

class Ui_Help(object):
    def setupUi(self, Help):
        Help.setObjectName("Help")
        Help.resize(251, 99)
        icon = QtGui.QIcon()
        icon.addPixmap(QtGui.QPixmap("logo.png"), QtGui.QIcon.Normal, QtGui.QIcon.Off)
        Help.setWindowIcon(icon)
        self.gridLayoutWidget = QtWidgets.QWidget(Help)
        self.gridLayoutWidget.setGeometry(QtCore.QRect(9, 9, 231, 81))
        self.gridLayoutWidget.setObjectName("gridLayoutWidget")
        self.gridLayout = QtWidgets.QGridLayout(self.gridLayoutWidget)
        self.gridLayout.setContentsMargins(0, 0, 0, 0)
        self.gridLayout.setObjectName("gridLayout")
        self.plainTextEdit = QtWidgets.QPlainTextEdit(self.gridLayoutWidget)
        font = QtGui.QFont()
        font.setFamily("Times New Roman")
        font.setPointSize(10)
        font.setBold(True)
        font.setWeight(75)
        self.plainTextEdit.setFont(font)
        self.plainTextEdit.setFrameShape(QtWidgets.QFrame.WinPanel)
        self.plainTextEdit.setFrameShadow(QtWidgets.QFrame.Sunken)
        self.plainTextEdit.setLineWidth(1)
        self.plainTextEdit.setSizeAdjustPolicy(QtWidgets.QAbstractScrollArea.AdjustIgnored)
        self.plainTextEdit.setReadOnly(True)
        self.plainTextEdit.setObjectName("plainTextEdit")
        self.gridLayout.addWidget(self.plainTextEdit, 0, 0, 1, 1)

        self.retranslateUi(Help)
        QtCore.QMetaObject.connectSlotsByName(Help)

Answer 1

Qt Designer 以简单的方式实现 View ，因此生成的类是面向 View 的，我们的工作是实现像 Ui_MainWindow 和 中那样的逻辑>MainWindow，与 Ui_Help 类似。对于您的情况，我建议您在构建 help_window.ui 时使用 Dialog 模板，但如果您选择 Widget 模板则没有问题，两者都非常兼容。

一个简单的解决方案是创建一个 QDialog 并在其中实现 Ui_Help View ，如下所示:

class MainWindow(QMainWindow, Ui_MainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)
        self.setupUi(self)
        self.Pophelp.triggered.connect(self.help_window)

    def help_window(self):
        # If you pass a parent (self) will block the Main Window,
        # and if you do not pass both will be independent,
        # I recommend you try both cases.
        widget = QDialog(self)
        ui=Ui_Help()
        ui.setupUi(widget)
        widget.exec_()

如果您想在 Ui_Help 中实现一些逻辑，我建议创建一个类似于 MainWindow 的类，如下所示:

class Help(QDialog, Ui_Help):
    def __init__(self, parent=None):
        super(Help, self).__init__(parent)
        self.setupUi(self)

class MainWindow(QMainWindow, Ui_MainWindow):
    def __init__(self, parent=None):
        super(MainWindow, self).__init__(parent)
        self.setupUi(self)
        self.Pophelp.triggered.connect(self.help_window)

    def help_window(self):
        widget = Help()
        widget.exec_()