php - 在 php 中执行 firebase : finding token in firebase

Question

我正在尝试使用 php 实现 firebase，这是我找到的链接:

https://github.com/ktamas77/firebase-php

这是一个例子。

const DEFAULT_URL = 'https://kidsplace.firebaseio.com/';
const DEFAULT_TOKEN = 'MqL0c8tKCtheLSYcygYNtGhU8Z2hULOFs9OKPdEp';
const DEFAULT_PATH = '/firebase/example';

$firebase = new \Firebase\FirebaseLib(DEFAULT_URL, DEFAULT_TOKEN);

// --- storing an array ---
$test = array(
    "foo" => "bar",
    "i_love" => "lamp",
    "id" => 42
);
$dateTime = new DateTime();
$firebase->set(DEFAULT_PATH . '/' . $dateTime->format('c'), $test);

// --- storing a string ---
$firebase->set(DEFAULT_PATH . '/name/contact001', "John Doe");

// --- reading the stored string ---
$name = $firebase->get(DEFAULT_PATH . '/name/contact001');

这是我的相同代码版本:

<?php

include 'firebaseLib.php';

const DEFAULT_URL = "https://third-try-dae0a.firebaseio.com";
const DEFAULT_TOKEN = 'AIzaSyDeGfW4hnT3a6AXDevJMhb4Pi1eMWQ7yvc';
const DEFAULT_PATH = '/third-try-dae0a';


$firebase = new \Firebase\FirebaseLib(DEFAULT_URL, DEFAULT_TOKEN);

// --- storing an array ---
$test = array(
    "foo" => "bar",
    "i_love" => "lamp",
    "id" => 42
);
$dateTime = new DateTime();
$firebase->set(DEFAULT_PATH . '/' . $dateTime->format('c'), $test);

// --- storing a string ---
$firebase->set(DEFAULT_PATH . '/name/contact001', "John Doe");

// --- reading the stored string ---
$name = $firebase->get(DEFAULT_PATH . '/name/contact001');

echo "done";



 ?>

我的代码不起作用...

我只想快速解释一下我在哪里找到 DEFAULT_TOKEN

那么 DEFAULT_PATH 呢？？

Answer 1

1) DEFAULT_PATH

默认路径是您的主项目路径。当您在 firebase 上创建新项目时。当您单击它时，您将获得它的路径。就像:https://your_project_name-xxx.firebaseio.com

2)DEFAULT_TOKEN

从 Firebase 控制台获取 token 的步骤

->登录打开并打开Fire Base控制台并选择项目

->从设置图标转到项目设置

->从菜单中选择服务帐户

->从左侧菜单中选择databasesecrets

->将鼠标悬停在 secret 上并单击显示按钮