python - 如何从日记条目制作字典？

Question

我正在尝试匹配日记条目日期的正则表达式，如果匹配，则将日期作为键，将后续条目作为值。

首先，我打算将其拆分为一个数组，并将每个奇数索引作为键，将其他索引作为值。

来源https://archive.org/stream/AnneFrankTheDiaryOfAYoungGirl_201606/Anne-Frank-The-Diary-Of-A-Young-Girl_djvu.txt

file = open(r"C:\Users\mmcgown\Desktop\School\MSDS452\FinalProject\TheDiaryOfAYoungGirl.txt","r")
s = file.read()

import re
r = '(SUNDAY|MONDAY|TUESDAY|WEDNESDAY|THURSDAY|FRIDAY|SATURDAY), (JANUARY|FEBRUARY|MARCH|APRIL|MAY|JUNE|JULY|AUGUST|SEPTEMBER|OCTOBER|NOVEMBER|DECEMBER) \d{1,2}, 19\d{2}\s*\n'
l = re.split(r,s)

l

但是，这只是在正则表达式之前和之后分开。因此，拆分不是正确的方法...因为由于某种原因它也在列表中给了我日期和月份。

'',
 'SUNDAY',
 'JUNE',
 'I\'ll begin from the ...

像下面这样分割这些日记条目的最简单方法是什么？

{ 'SUNDAY, JUNE 14, 1942' : 'I'll begin from the ...' },
{ 'MONDAY, JUNE 15, 1942' : 'I had my birthday ...'},
etc.

附注我还尝试了 for line in file 方法，但它变得越来越难看，所以我想我应该寻求正确解决方案的输入(我没有完成下面的内容)。

file = open(r"C:\Users\mmcgown\Desktop\School\MSDS452\FinalProject\TheDiaryOfAYoungGirl.txt","r")
dia = {}
for line in file:
    i = 0
    if re.match(r,line) and i == 0:
        dia = {line.rstrip() : ''}
    elif not re.match(r,line):
        line = last_line + line
    elif re.match(r,line) and (i != 0):
        dia.update({line: last_line})
    i = i + 1
    last_line = line

Answer 1

您可以使用此示例(我使用 OrderedDict 来按顺序保留字典中的日期，sample.txt 是您问题中的文本文件):

import re
from collections import OrderedDict

with open('sample.txt', 'r') as f_in:
    data = f_in.read()

data = re.findall(r'^([A-Z]+, [A-Z]+ \d+, \d+)(.*?)(?=(?:[A-Z]+, [A-Z]+ \d+, \d+)|(?:ANNE\'S DIARY ENDS HERE\.))', data, flags=re.M|re.DOTALL)

d = OrderedDict( data )

from pprint import pprint
pprint(d)

打印:

OrderedDict([('SUNDAY, JUNE 14, 1942',
              '\n'
              '\n'
              '\n'
              "I'll begin from the moment I got you, the moment I saw you "
              'lying on the table among\n'

...till

          "what I'd like to be and what I could be if ... if only there "
          'were no other people in\n'
          'the world.\n'
          '\n'
          'Yours, Anne M. Frank\n'
          '\n'
          '\n')])