java - Hibernate 用一个 session.save 保存许多不同的对象

Question

我有 4 个对象，我不想对每个对象都使用 session.save(obj) 。有没有办法在循环中或一次保存所有对象。

对于循环，我必须增加变量名称，但我认为这是不可能的，或者是解决问题的“好方法”。

    final Test a1 = new Test(6,"AA", 50, 100000,"20.04.2016","AAA", 111, "2016", "EEE");
    final Test a2 = new Test(7,"AB", 1050, 200000,"20.04.2016","BBB", 333, "2016", "EEE");
    final Test a3 = new Test(8,"AC", 40, 300000,"20.04.2016","CCC", 222, "2016", "UUU", "YY", 5, "SSS");
    final Test a4 = new Test(9,"PD", 400, 400000,"20.04.2016","DDD", 444, "2016", "CCC", "YY", 12, "RRR");

    session.beginTransaction();
    session.save(a1);
    session.save(a2);
    session.save(a3);
    session.save(a4);

    session.getTransaction().commit()

Answer 1

请使用数组

Test[] tests = new Test[] {new Test(), new Test()};

for(Test test : tests) {
  session.save(test);
}