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google-apps-script - "The coordinates of the range are outside the dimensions of the sheet"排序时出错

转载 作者:行者123 更新时间:2023-12-02 03:39:25 29 4
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我正在尝试创建一个脚本来对当前事件工作表/选项卡上的表格进行排序,但我收到无法识别的错误。我不断收到 The coordinates of the range are outside the dimensions of the sheet.。我的表中有从 columnA 到 columnQ 的数据。 columnA 中的数据是标识号,columnB 到 columnQ 包含公式。我的脚本做错了什么?

var sortFirst = 7; //index of column to be sorted by; 1 = column A, 2 = column B, etc.
var sortFirstAsc = true; //Set to false to sort descending

var sortSecond = 8;
var sortSecondAsc = true;

var sortThird = 9;
var sortThirdAsc = true;

var activeSheet = SpreadsheetApp.getActiveSheet();
var sheetName = activeSheet.getSheetName(); //name of sheet to be sorted
var sheet = SpreadsheetApp.getActive().getSheetByName(sheetName);
var range = sheet.getRange(2, 1, sheet.getLastRow(), sheet.getLastColumn());
range.sort([{column: sortFirst, ascending: sortFirstAsc}, {column: sortSecond, ascending: sortSecondAsc}, {column: sortThird, ascending: sortThirdAsc}]);

最佳答案

很有可能是线路上的错误

var range = sheet.getRange(2, 1, sheet.getLastRow(), sheet.getLastColumn());

很有可能的解决办法是改成

var range = sheet.getRange(2, 1, sheet.getLastRow() - 1, sheet.getLastColumn());

上面是因为范围从第 2 行开始并且因为工作表很可能在最后一行有内容。

相关

关于google-apps-script - "The coordinates of the range are outside the dimensions of the sheet"排序时出错,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/49157222/

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