java - org.hibernate.engine.jdbc.spi.SqlExceptionHelper 表 "Club"未找到

Question

我是 Java EE 新手，当我尝试通过 WEB-APP 从 HSQL DB 获取数据时，我在 Wildfly 控制台中收到此错误。

20:11:53,780 INFO  [stdout] (default task-12) Hibernate: select club0_.id as id1_2_, club0_.league_id as league_i4_2_, club0_.name as name2_2_, club0_.nbTitles as nbTitles3_2_ from "Club" club0_
20:11:53,785 WARN  [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (default task-12) SQL Error: 42102, SQLState: 42S02
20:11:53,785 ERROR [org.hibernate.engine.jdbc.spi.SqlExceptionHelper] (default task-12) Table "Club" not found; SQL statement:
select club0_.id as id1_2_, club0_.league_id as league_i4_2_, club0_.name as name2_2_, club0_.nbTitles as nbTitles3_2_ from "Club" club0_ [42102-173]
20:11:53,787 ERROR [org.jboss.as.ejb3.invocation] (default task-12) JBAS014134: EJB Invocation failed on component FootballBean for method public abstract java.util.List ch.hevs.footballservice.Football.getClubs(): javax.ejb.EJBException: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement
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Caused by: javax.persistence.PersistenceException: org.hibernate.exception.SQLGrammarException: could not prepare statement
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Caused by: org.hibernate.exception.SQLGrammarException: could not prepare statement
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Caused by: org.h2.jdbc.JdbcSQLException: Table "Club" not found; SQL statement:
select club0_.id as id1_2_, club0_.league_id as league_i4_2_, club0_.name as name2_2_, club0_.nbTitles as nbTitles3_2_ from "Club" club0_ [42102-173]
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这是我的俱乐部类(class):

import java.util.List;
import javax.persistence.Entity;
import javax.persistence.GeneratedValue;
import javax.persistence.GenerationType;
import javax.persistence.Id;
import javax.persistence.ManyToOne;
import javax.persistence.OneToMany;
import javax.persistence.Table;

@Entity
@Table(name="`Club`")
public class Club {

    // attributs
    @Id
    @GeneratedValue(strategy = GenerationType.SEQUENCE)
    private Long id;
    private String name;
    private int nbTitles;

    // relations
    @OneToMany(mappedBy = "club")
    private List<Player> players;

    @ManyToOne
    private League league;

    public Long getId() {
        return id;
    }

    public void setId(Long id) {
        this.id = id;
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public int getNbTitles() {
        return nbTitles;
    }

    public void setNbTitles(int nbTitles) {
        this.nbTitles = nbTitles;
    }

    public List<Player> getPlayers() {
        return players;
    }

    public void setPlayers(List<Player> players) {
        this.players = players;
    }

    public League getLeague() {
        return league;
    }

    public void setLeague(League league) {
        this.league = league;
    }

    // constructors
    public Club() {
    }
}

我的 persistence.xml

<?xml version="1.0" encoding="UTF-8"?>
<persistence xmlns="http://java.sun.com/xml/ns/persistence"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://java.sun.com/xml/ns/persistence
                http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd"
    version="1.0">

    <persistence-unit name="footballPU">
        <provider>org.hibernate.ejb.HibernatePersistence</provider>
        <class>ch.hevs.businessobject.Club</class>
        <class>ch.hevs.businessobject.League</class>
        <class>ch.hevs.businessobject.Player</class>
        <properties>
            <property name="hibernate.connection.url"
                value="jdbc:hsqldb:hsql://localhost/DB" />
            <property name="hibernate.connection.driver_class"
                value="org.hsqldb.jdbcDriver" />
            <property name="hibernate.connection.username" value="sa" />
            <property name="hibernate.connection.password" value="" />
            <property name="hibernate.show_sql" value="true" />
        </properties>
    </persistence-unit>
</persistence>

我使用以下 JUnit 测试创建数据库:

import junit.framework.TestCase;
import org.hibernate.cfg.Configuration;
import org.hibernate.tool.hbm2ddl.SchemaExport;
import org.junit.Test;

public class CreateSchemaTest extends TestCase {

        @Test
        public void test() {
            Configuration cfg = new Configuration();
            cfg.addAnnotatedClass(ch.hevs.businessobject.Player.class);
            cfg.addAnnotatedClass(ch.hevs.businessobject.Club.class);
            cfg.addAnnotatedClass(ch.hevs.businessobject.League.class);

            cfg.setProperty("hibernate.dialect",
                    "org.hibernate.dialect.HSQLDialect");
            cfg.setProperty("hibernate.connection.driver_class",
                    "org.hsqldb.jdbcDriver");
            cfg.setProperty("hibernate.connection.driver_class",
                    "org.hsqldb.jdbcDriver");
            cfg.setProperty("hibernate.connection.url",
                    "jdbc:hsqldb:hsql://localhost/DB");
            cfg.setProperty("hibernate.connection.username", "sa");

            new SchemaExport(cfg).setOutputFile("schema.ddl").create(false, true);
        }
    }

当我在 HSQL 数据库管理器中执行 EntityManager 生成的以下查询时，它工作正常..

select club0_.id as id1_2_, club0_.league_id as league_i4_2_, club0_.name as name2_2_, club0_.nbTitles as nbTitles3_2_ from "Club" club0_

有人可以帮助我吗？

Answer 1

谢谢您的回答。我在 persistence.xml 中添加了以下行，问题就解决了。

<property name="hibernate.hbm2ddl.auto" value="update" />