php - Laravel 中如何存储数组？

Question

有两个mysql表1.seats(id，number)，2.reservedseats(id，seat_id，sceering_id)。我在 show.blade 中将特定转向的所有座位显示为复选框:

{!!Form::model($screening,['method'=>'post', 'action'=> 
['ReserveController@store',$screening->auditorium->id]])!!}

<input type="hidden" name="screening_id" value="{{$screening->id}}">

@foreach($seats as $seat)

<label class="checkbox-inline">

{!!Form::checkbox('seat_id[]',$seat->id,null)!!} Number: {{$seat->number}}  

</label>

@endforeach

<div class='form-group'>

{!!Form::submit('Create Post',['class'=>'btn btn-primary '])!!}

</div>

{!!Form::close()!!}

当我单击一个复选框时，它会转到 Seat_id[] 数组。因此，我发送一个隐藏输入和一个带有 Seat_ids 的数组，然后我想将其存储在servedseats Mysql 表中。但在商店 Controller 中我遇到了问题。我正在尝试类似的事情:

public function store(Request $request){

 $screening_id = $request->screening_id;

 $seat_ids = $request->seat_id;

  foreach($seat_ids as $seat_id){

    Seatreserved::create($seat_id,$screening_id);

   }
}

所以它不起作用，但我该如何解决这个问题？

Answer 1

试试这个代码

public function store(Request $request)
{
    $screening_id = $request->screening_id;
    $seat_ids = $request->seat_id;

    foreach($seat_ids as $seat_id) {
        Seatreserved::create([
            'seat_id' => $seat_id,
            'screening_id' => $screening_id
        ]);
    }
}

你也可以使用

public function store(Request $request)
{
    $screening_id = $request->screening_id;
    $seat_ids = $request->seat_id;
    
    $data = [];
    foreach($seat_ids as $seat_id) {
        $data[] = [
            'seat_id' => $seat_id,
            'screening_id' => $screening_id
        ];
    }
    Seatreserved::insert($data);
}

这是执行此操作的更好方法，因为它将与数据库交互一次。