java - 正则表达式无法捕获所有匹配项

Question

这个问题已经有答案了:

Create array of regex matches (6 个回答)

已关闭 7 年前。

这是一个例子:

The two (Senior Officer Stuart & Officer Jess) were intercepted by Officer George.

现在，假设我有两个军衔“军官”和“高级军官”，并且想要将它们后面的名字替换为通用标记“PERSON”。正如您所看到的，排名后有三个名称 Stuart, Jess, George 。我不知道为什么我的正则表达式解决方案无法捕获所有这些。这是我的代码:

    public static void main(String[] args) {
    String input = "The two (Senior Officer Stuart & Officer Jess) were intercepted by Officer George.";
    ArrayList<String> ranks = new ArrayList<String>();
    ranks.add("Senior Officer");
    ranks.add("Officer");
    for (String rank : ranks) {
        Pattern pattern = Pattern.compile(".*" + rank + " ([a-zA-Z]*?) .*");
        Matcher m = pattern.matcher(input);
        if (m.find()) {
            System.out.println(rank);
            System.out.println(m.group(1));
        }
    }
}

这是它的输出:

Senior Officer
Stuart
Officer
Stuart

两次捕获斯图尔特(通过高级军官和军官)，但忽略杰西和乔治。我期望得到这个作为输出:

Senior Officer
Stuart
Officer
Stuart
Officer
Jess
Officer
George

Answer 1

这就足够了

for (String rank : ranks) {
    Pattern pattern = Pattern.compile("\\b" + rank + "\\s+([a-zA-Z]*)");
    Matcher m = pattern.matcher(input);
    while (m.find()) {
        System.out.println(rank);
        System.out.println(m.group(1));
    }
}

<强> Ideone Demo

正则表达式分解(根据评论)

Officer #Match Officer literally
 ( #Capturing group
  (?: #Non-capturing group
    \s #Match space
     (?!(?:Senior\s+)?Officer) #Negative lookahead assures that its impossible to match the word Senior(which is optional) and Officer literally
    [A-Z][a-zA-Z]* #Match capital letter followed by combination of capital and small letter
  )* #Repeat the previous step any number of time till one of the condition of first letter being capital fails or word Officer is found
 )