java - 如何忽略异常并继续下一个值

Question

嗨，我正在尝试将值列表传递给google api。如果api抛出任何异常，它就会退出循环。即使抛出任何错误，我也需要继续下一个值。下面是我的代码。

while (iterator.hasNext()) {
       Object element = iterator.next();
       String postcode = element.toString().trim();
       String latLongs[] = getLatLongPositions(postcode);
       System.out.println("Latitude: " + latLongs[0] + " and Longitude: " + latLongs[1]);
       System.out.println(postcode);
   }

   public static String[] getLatLongPositions(String address) throws Exception {

       int responseCode = 0;
       String api = "http://maps.googleapis.com/maps/api/geocode/xml?address=" + URLEncoder.encode(address, "UTF-8") + "&sensor=true";
       URL url = new URL(api);
       HttpURLConnection httpConnection = (HttpURLConnection) url.openConnection();
       httpConnection.connect();
       responseCode = httpConnection.getResponseCode();
       if (responseCode == 200) {
           DocumentBuilder builder = DocumentBuilderFactory.newInstance().newDocumentBuilder();;
           org.w3c.dom.Document document = builder.parse(httpConnection.getInputStream());
           XPathFactory xPathfactory = XPathFactory.newInstance();
           XPath xpath = xPathfactory.newXPath();
           XPathExpression expr = xpath.compile("/GeocodeResponse/status");
           String status = (String) expr.evaluate(document, XPathConstants.STRING);
           if (status.equals("OK")) {
               expr = xpath.compile("//geometry/location/lat");
               String latitude = (String) expr.evaluate(document, XPathConstants.STRING);
               expr = xpath.compile("//geometry/location/lng");
               String longitude = (String) expr.evaluate(document, XPathConstants.STRING);
               return new String[] {
                   latitude, longitude
               };
           } else {

               throw new Exception("Error from the API - response status: " + status);
           }
       }
       return null;
   }

即使我提到返回 null 而不是抛出新异常。它也会显示空指针异常。任何帮助将不胜感激。

Answer 1

在这部分放置 try/catch

...
try{
    String latLongs[] = getLatLongPositions(postcode);
    System.out.println("Latitude: " + latLongs[0] + " and Longitude: " + latLongs[1]);
    System.out.println(postcode);
}catch(Exception e){
    ...
}