java - 使用条件java删除重复的列表对象

Question

我有数组列表对象，但我想过滤删除数据(如果一天内有任何重复的 ID)。

这是我的代码

public static void main(String[] args) {

        ArrayList<UniqueCompletedChat> al = new ArrayList<UniqueCompletedChat>();
        al.add(new UniqueCompletedChat("2015-11-01", "D01"));
        al.add(new UniqueCompletedChat("2015-11-01", "D01"));
        al.add(new UniqueCompletedChat("2015-11-01", "D02"));
        al.add(new UniqueCompletedChat("2015-11-01", "D01"));
        al.add(new UniqueCompletedChat("2015-11-02", "D01"));
        al.add(new UniqueCompletedChat("2015-11-02", "D02"));
        al.add(new UniqueCompletedChat("2015-11-02", "D03"));
        al.add(new UniqueCompletedChat("2015-11-02", "D02"));
        al.add(new UniqueCompletedChat("2015-11-02", "D02"));
        al.add(new UniqueCompletedChat("2015-11-03", "D01"));

        List<UniqueCompletedChat> result = new ArrayList<UniqueCompletedChat>();
        Set<String> titles = new HashSet<String>();

        for (UniqueCompletedChat u : al) {
            if (titles.add(u.getIdDoctor()) || titles.add(u.getDate())) {
                result.add(u);
            }
        }

        for(UniqueCompletedChat u : result){
            System.out.print(u.getDate() + " || ");
            System.out.print(u.getIdDoctor());
            System.out.println("");
        }
}

class UniqueCompletedChat {
    private String date;
    private String idDoctor;

    public UniqueCompletedChat(String date, String idDoctor) {
        this.date = date;
        this.idDoctor = idDoctor;
    }

    public String getDate() {
        return date;
    }

    public void setDate(String date) {
        this.date = date;
    }

    public String getIdDoctor() {
        return idDoctor;
    }

    public void setIdDoctor(String idDoctor) {
        this.idDoctor = idDoctor;
    }
}

这是我的代码的输出

我的目标期望结果

如何达到我的期望？有什么方法可以优雅地解决这个问题吗？

Answer 1

我认为该错误来自此 LOC:

if (titles.add(u.getIdDoctor()) || titles.add(u.getDate())) {
    result.add(u);
}

尝试像这样组合并检查它:

if (titles.add(u.getIdDoctor() + u.getDate())) {
    result.add(u);
}

当然，您可以使用 StringBuilder 以获得更好的性能。