jenkins - 在 slave 上运行 jenkins DSL 脚本

Question

我有一个 Build Flow具有用于配置流程的 DSL 脚本的项目。

这是我的脚本:

def envVars = build.getEnvironment(listener)
def revision = envVars.get("GIT_COMMIT")
def workspace = envVars.get("WORKSPACE")
println "env vars: " + envVars
println "workspace: " + workspace
println "revision: " + revision
def command = workspace+"""/scripts/my_script.sh"""
def proc = command.execute()
proc.waitFor()
println "return code: ${proc.exitValue()}"
println "stderr: ${proc.err.text}"
println "stdout: ${proc.in.text}" 

parallel (
  { 
    build("job1", git_branch: revision)
  },
  { 
    build("job2", git_branch: revision) 
  },
  { 
    build("job3", git_branch: revision) 
  }
)

在我的作业配置中，我检查了Restrict where this project can be run并给出了正确的从标签。

我的作业因以下错误而失败:

ERROR: Failed to run DSL Script
java.io.IOException:
  Cannot run program "/home/jenkins/workspace/my-flow-job/scripts/my_script.sh":
    error=2, No such file or directory

我发现 DSL 脚本在主节点而不是从节点上运行。

如何在从机上运行 DSL？ (或者至少在从机上执行脚本)

谢谢

Answer 1

您应该为当前 channel 创建一个文件路径，并创建一个启动器来启动您的脚本。像下面这样的东西应该适合你。

def envVars = build.getEnvironment(listener)
def workspace = envVars.get("WORKSPACE")
def command = workspace+"""/scripts/my_script.sh"""
def channel = build.workspace.channel
def fp = build.workspace.toString()
def workspacePath = new hudson.FilePath(channel, fp)

def launcher = workspacePath.createLauncher(hudson.model.TaskListener.NULL);
def starter = launcher.launch().pwd(workspacePath).stdout(out).stderr(out).cmdAsSingleString(command)
starter.join()