java - 如何正确使用java中的\n

Question

每当我编译并运行代码时，输​​出都会变得一团糟，我希望有人可以告诉我如何使我的输出看起来不错。

import java.util.*;
public class JavaApplication3 {
    static Scanner sc = new Scanner(System.in);
    public static void main(String[] args) {
        int NumPerHamper;
        int NumHampersMade;
        int NumItemsLeftOver;
        int NumAvalable;
        double ValuePerHamper;
        double ItemCost;
        double ValueAllotedHamper;
        double ValueItemsLeftOver;
        String name="";
        Date TheDate = new Date();

        System.out.println("Enter the number of avaliable mac and cheese");
        NumAvalable = sc.nextInt();

        System.out.println("Enter the number of items per hamper");
        NumPerHamper = sc.nextInt();

        System.out.println("Price Of Item");
        ItemCost = sc.nextDouble();

        NumHampersMade = NumAvalable / NumPerHamper;
        NumItemsLeftOver = NumAvalable % NumPerHamper;
        ValuePerHamper = NumPerHamper * ItemCost;
        ValueAllotedHamper = ValuePerHamper * NumHampersMade;
        ValueItemsLeftOver = NumItemsLeftOver * ItemCost;
        System.out.printf("\n");
        System.out.printf(TheDate + "\n");
        System.out.printf("Amount of Hampers Made: ", NumHampersMade,"\n");
        System.out.printf("The Items Left Over is: ", NumItemsLeftOver,"\n");
        System.out.printf("Each Value Of the Hampers are: $%.2f.", ValuePerHamper,"\n");
        System.out.printf("The Price Of All The Hampers Is: $%.2f.", ValueAllotedHamper,"\n");
        System.out.printf("The Value Of Mac And Cheese Is: $%.2f.", ValueItemsLeftOver,"\n");
    }
}

Answer 1

这是不对的:

System.out.printf("Each Value Of the Hampers are: $%.2f.", ValuePerHamper,"\n");

第一个参数(格式字符串)是替换“格式说明符”或占位符后实际打印的字符串。该字符串中的格式说明符(例如 %.2f)将替换为其他参数。因此，第二个参数 ValuePerHamper 用于第一个说明符 %.2f；第三个参数 \n 用于第二个说明符 ---um，但没有任何其他说明符，因此根本不会使用它。

您想要将 \n 放入格式字符串中:

System.out.printf("Each Value Of the Hampers are: $%.2f.\n", ValuePerHamper);

(printf 还允许您使用 %n 而不是 \n，这更便携，因为它也适用于 Windows 系统转到新行需要 \r\n 而不是 \n。)