Java:只是在空格后对字符串进行排序？

Question

我正在制作一个根据姓氏对姓名进行排序的程序，但是用户输入了全名，例如“John Smith”，并且我无法让它按空格后的姓名进行排序。

似乎只想按输入的名字排序而忽略最后一个，但我想按姓氏排序

        System.out.println("Welcome to name sorter program");

    //Set max names to 10
    String [] names = new String[10];
    String temp;
    for (int i = 0; i < names.length; i++)
    {
        System.out.println("Enter person " +(i + 1));
        //Name entered is assigned to each array slot
        names[i] = userInput.nextLine();
    }
        for (int i = 0; i < names.length; i++)
    {
        for (int j = i + 1; j < names.length; j++ )
        {
            if (names[i].compareTo(names[j]) > 0)
            {
                temp = names[i];
                names[i] = names[j];
                names[j] = temp;
            }
        }
    }
    System.out.println("Sorted Names Are...");
    for (int i = 0; i < names.length - 1; i++)
    {
        System.out.println(names[i]);
    }
        System.out.println(names[names.length - 1]);
}

Answer 1

我的答案几乎与@BahramdunAdil相同:

public class Main {

    public static void main(String[] args) {

        final int MAX = 10;

        Scanner userInput = new Scanner(System.in);

        List<Person> names = new ArrayList<Person>();

        System.out.println("Welcome to name sorter program!\n");

        for (int i = 0; i < MAX; i++) {
            System.out.println("Enter person " + (i + 1) + ":");
            names.add(new Person(userInput.nextLine()));
        }

        userInput.close();

        Collections.sort(names);

        System.out.println("\nSorted Names Are...");

        for (Person name : names)
            System.out.println(name);
    }

}

也就是说，您可以简化代码，创建一个实现 Comparable 的 Person 类:

public class Person implements Comparable<Person> {
    private String firstName;
    private String lastName;

    public Person(String name) {
        this.firstName = name.split(" ")[0];
        this.lastName = name.split(" ")[1];
    }

    public String getFirstName() {
        return firstName;
    }

    public String getLastName() {
        return lastName;
    }

    @Override
    public int compareTo(Person o) {
        return lastName.compareTo(o.getLastName());
    }

    @Override
    public String toString() {
        return firstName + " " + lastName;
    }
}

输入:

Welcome to name sorter program!

Enter person 1:
Bill Gates
Enter person 2:
Amancio Ortega
Enter person 3:
Warren Buffett
Enter person 4:
Carlos Slim Helu
Enter person 5:
Jeff Bezos
Enter person 6:
Mark Zuckerberg
Enter person 7:
Larry Ellison
Enter person 8:
Michael Bloomberg
Enter person 9:
Charles Koch
Enter person 10:
David Koch

输出:

Sorted Names Are...
Jeff Bezos
Michael Bloomberg
Warren Buffett
Larry Ellison
Bill Gates
Charles Koch
David Koch
Amancio Ortega
Carlos Slim
Mark Zuckerberg