c++ - 如何使用地址模型标志在 Windows 上为 Visual Studio 构建 64 位 boost？

Question

我正在尝试使用以下说明在 Visual Studio 的 x64 终端上构建 boost:https://www.boost.org/doc/libs/1_62_0/more/getting_started/windows.html#get-boost

我愿意:

boost

然后

.\b2 地址模型=64

但它总是说:

C:\boost_1_70_0>.\b2 address-model=64
Performing configuration checks

    - default address-model    : 32-bit
    - default architecture     : x86

Building the Boost C++ Libraries.

...

然后继续构建所有内容的 32 位版本。我知道这一点是因为当我尝试对 CMake 之类的东西使用 boost 时，它会提示它是 32 位的:

C:\src\SimpleAmqpClient\simpleamqpclient-build>cmake -DBOOST_ROOT=C:\boost_1_70_0 -DBOOST_LIBRARYDIR=C:\boost_1_70_0\stage\lib ..
-- Found Boost 1.70.0 at C:/Program Files/boost/lib/cmake/Boost-1.70.0
--   Requested configuration: QUIET REQUIRED COMPONENTS chrono;system
-- Found boost_headers 1.70.0 at C:/Program Files/boost/lib/cmake/boost_headers-1.70.0
-- Found boost_chrono 1.70.0 at C:/Program Files/boost/lib/cmake/boost_chrono-1.70.0
-- No suitable boost_chrono variant has been identified!
--   libboost_chrono-mgw82-mt-d-x32-1_70.a (32 bit, need 64)
--   libboost_chrono-mgw82-mt-x32-1_70.a (32 bit, need 64)
CMake Error at C:/Program Files/boost/lib/cmake/Boost-1.70.0/BoostConfig.cmake:95 (find_package):
  Found package configuration file:

    C:/Program Files/boost/lib/cmake/boost_chrono-1.70.0/boost_chrono-config.cmake

  but it set boost_chrono_FOUND to FALSE so package "boost_chrono" is
  considered to be NOT FOUND.  Reason given by package:

  No suitable build variant has been found.

Call Stack (most recent call first):
  C:/Program Files/boost/lib/cmake/Boost-1.70.0/BoostConfig.cmake:124 (boost_find_dependency)
  C:/Program Files/CMake/share/cmake-3.15/Modules/FindBoost.cmake:273 (find_package)
  CMakeLists.txt:35 (FIND_PACKAGE)


-- Configuring incomplete, errors occurred!
See also "C:/src/SimpleAmqpClient/simpleamqpclient-build/CMakeFiles/CMakeOutput.log".

那么是的，我如何构建 64 位？

Answer 1

请参阅我在这里给出的答案:How to build Boost 1.64 in 64 bits?
如果您想显式指定工具集，则 Visual Studio 2019 为 toolset=msvc-14.2

注意:确保从 Visual Studio 工具命令提示符
构建它并忽略控制台上的 - default address-model : 32-bit 输出，它会构建 64 位二进制文​​件。