java - 为什么我的 if else 语句不执行？

Question

首先，我发现另外两个线程也有类似的问题。问题是他们没有使用 right equal sign for string而不是formatting the if statements correctly针对他们的特殊问题。

对于我的作业，我需要创建一个名为 Pig 的游戏，其中玩家与计算机在掷骰子对中首先获得 100 分。如果玩家一回合掷出 1 分，则他们不会获得额外分数。如果玩家掷出两个 1，则他们将失去所有分数。我还没有对计算机的回合进行编码，只是关注玩家。请告诉我我做错了什么。预先非常感谢您。

import java.util.Scanner;
public class FourFive
{
    public static void main (String[] args)
    {
    Pigs myopp = new Pigs();
    Scanner scan = new Scanner (System.in);
    final int Round = 20;
    int num1, num2;

    int roundTotal = 0;
    int playerTotal = 0;
    int compTotal = 0;
    int win = 100;
    int turnOver = 1;
    Pigs die1 = new Pigs();
    Pigs die2 = new Pigs();
    String play = "y";
    System.out.println("Type y to play");
    play = scan.nextLine();

<小时/>

    while (play.equalsIgnoreCase("y"))
    {
        for (int roll = 1; roll <= 6; roll++)//Each die has 6 sides
        {
            num1 = die1.roll();//rolls first die
            num2 = die2.roll();//rolls second die
            int points = num1 + num2;// adds dies up to get total for this turn
            System.out.println("You roll " + num1 + " and " + num2);

            if (num1 == 1 || num2 == 1)//If either of the dies roll 1, no points 
                points += 0;
            else if (num1 == 1 && num2 == 1)//if both are 1, lose ALL points
                playerTotal = 0;
            else
                System.out.println("you earned " + points + " this round");

            playerTotal += points; total number of points per round added   
            System.out.println("You have a total of " + playerTotal);


            System.out.println("Type y to play");
            play = scan.nextLine();
      }
    }
 }
}

我的输出:

Type y to play
y
You roll 4 and 2
you earned 6 this round
You have a total of 6
Type y to play
y
You roll 6 and 5
you earned 11 this round
You have a total of 17
Type y to play
y
You roll 1 and 1
You have a total of 19 //total should be 0 because of the two 1's
Type y to play
y
You roll 6 and 3
you earned 9 this round
You have a total of 28
Type y to play
y
You roll 1 and 1
You have a total of 30 //total should be 0 because of the two 1's
Type y to play
y
You roll 6 and 4
you earned 10 this round
You have a total of 40
Type y to play
y
You roll 5 and 2
you earned 7 this round
You have a total of 47
Type y to play
y
You roll 5 and 1
You have a total of 53 //shouldn't add any additional points because of the "1"
Type y to play

Answer 1

如果 num1 为 1，则第一个 if 条件采用该值。它不会检查“else if”条件。类似地，如果 num2 为 1，则 if 条件采用该值。所以把你的 && 条件放在第一位。

        if (num1 == 1 && num2 == 1)//if both are 1, lose ALL points
            playerTotal = 0;
        else if (num1 == 1 || num2 == 1)//If either of the dies roll 1, no points 
            points += 0;
        else
            System.out.println("you earned " + points + " this round");