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spring-amqp - 如何手动从 RabbitMQ Spring 拉取消息

转载 作者:行者123 更新时间:2023-12-02 03:11:01 26 4
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我需要从 RabbitMQ 队列中手动提取记录,而不是自动提取。以下是我为此创建的内容。但是,我想知道是否有更好的 Spring/RabbitMQ 方式来做到这一点?

您会注意到 channel.basicAck 和 channel.basicNack 的使用。如果/当消费者抛出异常时,我将它们放置在他们可以确认/NotAcknowledge的地方,以便记录可以保持排队状态。

我会使用 RabbitTemplate.receiveAndConvert,但这会自动确认记录,即使可能有不应该确认的原因。

import java.util.Properties;
import java.util.function.Consumer;

import org.slf4j.Logger;
import org.slf4j.LoggerFactory;
import org.springframework.amqp.core.AmqpAdmin;
import org.springframework.amqp.core.Message;
import org.springframework.amqp.core.MessageProperties;
import org.springframework.amqp.rabbit.core.ChannelCallback;
import org.springframework.amqp.rabbit.core.RabbitAdmin;
import org.springframework.amqp.rabbit.core.RabbitTemplate;
import org.springframework.amqp.rabbit.support.DefaultMessagePropertiesConverter;
import org.springframework.amqp.rabbit.support.MessagePropertiesConverter;
import org.springframework.amqp.support.converter.MessageConverter;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;

import com.rabbitmq.client.Channel;
import com.rabbitmq.client.DefaultConsumer;
import com.rabbitmq.client.GetResponse;

@Service
public class RabbitAdminServices {

private static final Logger logger = LoggerFactory.getLogger(RabbitAdminServices.class);

@Autowired
AmqpAdmin rabbitAdmin;

@Autowired
RabbitTemplate rabbitTemplate;

@Autowired
MessageConverter messageConverter;

private volatile MessagePropertiesConverter messagePropertiesConverter = new DefaultMessagePropertiesConverter();

public int getCount(String queueName) {

Properties properties = rabbitAdmin.getQueueProperties(queueName);
return (Integer)properties.get(RabbitAdmin.QUEUE_MESSAGE_COUNT);
}

public <T> void processQueue(String queueName, Integer count, Class<T> clazz, Consumer<T> consumer) {

int reprocessCount = getCount(queueName);
int requestCount = reprocessCount;
if(count != null) {
requestCount = count;
}
for(int i = 0; i < reprocessCount && i < requestCount; i++) {
rabbitTemplate.execute(new ChannelCallback<T>() {

@Override
public T doInRabbit(Channel channel) throws Exception {
GetResponse response = channel.basicGet(queueName, false);
T result = null;
try {
MessageProperties messageProps = messagePropertiesConverter.toMessageProperties(response.getProps(), response.getEnvelope(), "UTF-8");
if(response.getMessageCount() >= 0) {
messageProps.setMessageCount(response.getMessageCount());
}
Message message = new Message(response.getBody(), messageProps);
result = (T)messageConverter.fromMessage(message);
consumer.accept(result);
channel.basicAck(response.getEnvelope().getDeliveryTag(), false);
}
catch(Exception e) {
channel.basicNack(response.getEnvelope().getDeliveryTag(), false, true);
}
return result;
}
});

}
}
}

最佳答案

您的解决方案对于模板的当前状态是正确的;我们可能应该考虑向 RabbitTemplate 添加重载方法, 就像是

<T> void template.receiveAndConvert(..., Class<T> clazz, Consumer<T> consumer);

并根据消费者是否抛出异常来设置模板 ack/nack。这将避免您必须在代码中进行转换。

关于spring-amqp - 如何手动从 RabbitMQ Spring 拉取消息,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40093727/

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