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SQL Server 错误简化代码由于多个联接

转载 作者:行者123 更新时间:2023-12-02 03:09:56 25 4
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我需要一种替代方法来简化这段代码。

此代码根据贷款还款计划计算客户余额的年龄。过滤器是1-7天、8-30、31-60 ....等等,直到达到181及以上

with membersWithLoans as -- gets members with loan
(
select
a.memberid, a.loanid, a.loanamt, a.intamt
from
loanmst a
where
loandt <= '12/19/2016'
and status = 'O'
)
,selectPaymentToDate as -- gets payments of the members to date
(
select
b.loanid, sum(a.princollamt) as princollamt1,
sum(a.intcollamt) as intcollamt1
from
collectiondtl a
inner join
membersWithLoans b on a.loanid = b.loanid
where
a.accdate <= '12/19/2016'
group by
b.loanid)
,selectBalanceToDate as -- gets the balance of member to date
(
select
b.loanid,
sum(a.princeamt) as prinBalanceToDate,
sum(a.instamt) as intBalanceToDate,
sum(a.insamt) as insuBalanceToDate
from
loandtl a
inner join
membersWithLoans b on a.loanid = b.loanid
where
a.duedt <= '12/19/2016'
group by
b.loanid)
, combineBalanceWithpayment as -- combine payment and balance
(
select a.loanid,a.loanamt, a.intamt,
(case
when b.prinBalanceToDate is null then 0
else b.prinBalanceToDate end) as prinBalanceToDate2,
(case
when b.intBalanceToDate is null then 0
else b.intBalanceToDate end) as intBalanceToDate2,
(case
when b.insuBalanceToDate is null then 0
else b.insuBalanceToDate end) as insuBalanceToDate2,
(case
when c.princollamt1 is null then 0
else c.princollamt1 end) as PrincipalCollectiontoDate,
(case
when c.intcollamt1 is null then 0
else c.intcollamt1 end) as IntCollectiontoDate,

cast(((case
when b.prinBalanceToDate is null then 0
else b.prinBalanceToDate
end)
-
(case
when c.princollamt1 is null then 0
else c.princollamt1 end))as decimal(10,2)) as Arrears
from
membersWithLoans a
left join selectBalanceToDate b
on a.loanid=b.loanid
left join selectPaymentToDate c
on a.loanid=c.loanid
)

,filterNegativeArrears as
(
select *
from
combineBalanceWithpayment
where Arrears > 0
)

上面的代码获取成员(member)信息

,select1To7days as -- this code gets amount to be paid in a specific schedule
(
select b.loanid,
sum((case
when a.princeamt is null then 0
else a.princeamt end))as prin7Daysbalance

from loandtl a
inner join membersWithLoans b
on a.loanid=b.loanid
where
a.duedt > DATEADD(day,-7,'12/19/2016')
and
a.duedt<='12/19/2016'
group by b.loanid
)

,select8to30days as -- this code gets amount to be paid in a specific schedule
(
select b.loanid,
sum((case
when a.princeamt is null then 0
else a.princeamt end))as prin8To30Daysbalance
from loandtl a
inner join membersWithLoans b
on a.loanid=b.loanid
where
a.duedt<=DATEADD(day,-7,'12/19/2016')
and a.duedt > DATEADD(day,-30,'12/19/2016')
group by b.loanid
)

-- and so on ..... the filters for schedule is compose of 31 to 60days, 61 to 90 days,
--121 to 180 days, 181 and above. there is no pattern since it the requirement on days may change


, computePar1To7days as -- computes the 1 to 7 days
(
select a.loanid, cast((a.arrears - a.Par1To7days) as decimal(10,2)) as deductedArrears, a.Par1To7days
from
(
select a.loanid,a.arrears,
cast((case
when a.arrears >= b.prin7Daysbalance then b.prin7Daysbalance -- if the arrears is greater than the 7days balance to be collected then it will be show
else a.arrears end)as decimal(10,2))as Par1To7days -- else the remaining is the arrears
from
filterNegativeArrears a
left join select1To7days b
on a.loanid=b.loanid
) a
where cast((a.arrears - a.Par1To7days) as decimal(10,2)) > 0
)

,computePar8To30days as -- computes the 8 to 30 days
(
select a.loanid, cast((a.arrears - a.Par8To30days)as decimal(10,2)) as deductedArrears, a.Par8To30days
from
(
select a.loanid, a.deductedArrears as arrears,
cast((case
when (a.deductedArrears) > 0
then
(case
when (a.deductedArrears)>= b.prin8To30Daysbalance
then b.prin8To30Daysbalance
else (a.deductedArrears)
end)
else 0 end)as decimal(10,2))as Par8To30days

from computePar1To7days a
left join select8To30days b
on a.loanid=b.loanid
) a
where cast((a.arrears - a.Par8To30days) as decimal(10,2)) > 0
)
-- so on until all par is computed. 31 to 60 days, 61 to 90 days,
--121 to 180 days, 181 and above. there is no pattern since it the requirement on days may change

上面的代码从特定的时间表中获取数据的总和,比如1-7天、8-30天、31-60天、61-90天、121-180天、181及以上

select a.*,
b.Par1To7days,
c.Par8To30days,
d.Par31To60days,
e.Par61To90days,
f.Par91To120days,
g.Par121To180days --,
--h.Par181AndAbovedays
from

filterNegativeArrears a
left join computePar1To7days b
on a.loanid=b.loanid
left join computePar8To30days c
on a.loanid=c.loanid
left join computePar31To60days d
on a.loanid=d.loanid
left join computePar61To90days e
on a.loanid=e.loanid
left join computePar91To120days f
on a.loanid=f.loanid
left join computePar121To180days g
on a.loanid=g.loanid
--left join computePar181AndAbovedays h
-- on a.loanid=h.loanid

上面的代码加入了计算出来的年龄

代码运行良好,计算正常

enter image description here

但是当我在选择中添加更多连接时出现错误

left join computePar181AndAbovedays h
on a.loanid=h.loanid

问题是我开始遇到错误:

enter image description here

An expression services limit has been reached. Please look for potentially complex expressions in your query, and try to simplify them.

我还需要更多表来加入我的查询。

您能否建议简化此查询的方法非常感谢

最佳答案

您显然在那里遇到了限制,并且您的查询不可能达到该限制。按照错误消息中给出的建议进行操作:简化。

如何?那么您已经定义了大量 CTE。编写查询的另一种方法是在实际查询之前在临时表中具体化 CTE,然后改用临时表。


例如,这个 CTE:

membersWithLoans as -- gets members with loan
(
select a.memberid, a.loanid,a.loanamt,a.intamt
from loanmst a
where loandt<='12/19/2016'
and status = 'O'
)

可以具体化为临时表:

select a.memberid, a.loanid,a.loanamt,a.intamt
into #membersWithLoans
from loanmst a
where loandt<='12/19/2016'
and status = 'O'

这将创建一个临时表 #membersWithLoans可用于进一步创建临时表或用于最终查询。

为了进一步说明,假设您已将所有 CTE 物化为临时表,您将不再有 WITH条款。然后,您最终会在最终 SELECT 中使用临时表查询:

-- create all temporary tables (one of them being #filterNegativeArrears)

select
a.*,
-- the rest of your selections
from
#filterNegativeArrears a
-- the rest of the joined temporary tables
-- the rest of your query (WHERE, ORDER BY etc)

关于SQL Server 错误简化代码由于多个联接,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/40501108/

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