python - 使用 Python 的 XPATH 解析 XML

Question

我是 Python 新手 - 才几天 - 我希望得到一些帮助。

我想编写一个 python 代码来解析下面的 XML，如下所示:-

ServingCell----------NeighbourCell
L41_NBR3347_1----------L41_NBR3347_2
L41_NBR3347_1----------L41_NBR3347_3
L41_NBR3347_1----------L41_NBR3349_1
L41_NBR3347_1----------L41_NBREA2242_1

<LteCell id="L41_NBR3347_1">
 <attributes>
  <absPatternInfoTdd><unset/></absPatternInfoTdd>
  <additionalSpectrumEmission>1</additionalSpectrumEmission>
  <additionalSpectrumEmissionList><unset/></additionalSpectrumEmissionList>
  <LteSpeedDependentConf id="0">                   
    <attributes>                                    
     <tReselectionEutraSfHigh>lDot0</tReselectionEut
     <tReselectionEutraSfMedium>lDot0</tReselectionE
    </attributes>                                   
   </LteSpeedDependentConf>                         
   <LteNeighboringCellRelation id="L41_NBR3347_2">  
    <attributes>                                    
     <absPatternInfo><unset/></absPatternInfo>      
   </LteNeighboringCellRelation>                    
   <LteNeighboringCellRelation id="L41_NBR3347_3">  
    <attributes>                                    
     <absPatternInfo><unset/></absPatternInfo>      
   </LteNeighboringCellRelation>                    
   <LteNeighboringCellRelation id="L41_NBR3349_1">  
    <attributes>                                    
     <absPatternInfo><unset/></absPatternInfo>                            
   </LteNeighboringCellRelation>                    
   <LteNeighboringCellRelation id="L41_NBREA2242_1">
    <attributes>                                    
     <absPatternInfo><unset/></absPatternInfo>      
     <absPatternInfoTdd><unset/></absPatternInfoTdd>

Answer 1

首先，您生成的 xml 路径不正确:您需要关闭打开的标签。例如属性已打开但未关闭。

   <LteNeighboringCellRelation id="L41_NBR3349_1">  
       <attributes>                                    
       <absPatternInfo>
          <unset/>
       </absPatternInfo>                            
   </LteNeighboringCellRelation>

我重构(并稍微简化了一点)xml 来纠正它。

<LteCell id="L41_NBR3347_1">   
   <attributes>                    
      <LteNeighboringCellRelation id="L41_NBR3347_2">                                          
      </LteNeighboringCellRelation>                    
      <LteNeighboringCellRelation id="L41_NBR3347_3">         
      </LteNeighboringCellRelation>                    
      <LteNeighboringCellRelation id="L41_NBR3349_1">                                                             
      </LteNeighboringCellRelation>                    
      <LteNeighboringCellRelation id="L41_NBREA2242_1">
      </LteNeighboringCellRelation>
   </attributes> 
</LteCell> 

这是解析和显示它的代码。

import xml.etree.ElementTree as ET
tree = ET.parse("XmlExample.xml")
result = ''
root = tree.getroot()

for e in tree.findall('./attributes/LteNeighboringCellRelation'):#attributes/LteNeighboringCellRelation
    print(root.attrib['id']+'----------'+e.attrib.get('id'))

希望有帮助，