java - 将 cURL 调用转换为 Java

Question

我想将以下 cURL 转换为 java 代码:

curl -i -b 'JSESSIONID=ekl23l2-3321-1930-b889-kelwek23b8v9; Path=/; HttpOnly' http://127.0.0.1:8080/api/library

在上面的调用中，JSESSIONID cookie 负责确保服务器对调用进行身份验证。我想出了以下 Java 代码:

    CloseableHttpClient httpClient = HttpClientBuilder.create().build();
    HttpGet httpGet = new HttpGet("http://127.0.0.1:8080/api/library");
    httpGet.addHeader("Set-Cookie","JSESSIONID=ekl23l2-3321-1930-b889-kelwek23b8v9; Path=/; HttpOnly");
    HttpResponse httpResponse = httpClient.execute(httpGet);
    BufferedReader rd = new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent()));
    StringBuffer result = new StringBuffer();
    String line = "";
    while ((line = rd.readLine()) != null) {
        result.append(line);
    }
    JSONObject o = new JSONObject(result.toString());
    rd.close();
    httpClient.close();     

但是，这对我不起作用，因为服务器提示未经授权的访问。当用户未经授权时会发生此响应，这意味着 JSESSIONID 未正确设置。任何人都可以评论这是否是将 cURL 转换为 Java 的正确方法吗？

Answer 1

您正在使用Set-Cookie(来自响应 header 中的服务器)，而它应该只是Cookie:(来自请求 header 中的客户端)。

httpGet.addHeader("Cookie","JSESSIONID=ekl23l2-3321-1930-b889-kelwek23b8v9; Path=/; HttpOnly");