java - 在 java 对象数组中执行按顺序(按字母顺序)添加

Question

我有下面的一段代码，只是将新元素添加到末尾，但我希望能够添加按目标名称按字母顺序排序的每个新元素。不确定我是否必须在添加后对列表进行排序，或者通过先检查然后添加来插入新对象。无论哪种情况，都不知道如何去做。

public void add()
    {
        int newRating =-1;
        in = new Scanner(System.in);
        if((lastElement+1) < MAX_ELEMENT)    //MAX_ELEMENT =100
        {
            System.out.print("Enter the Name: ");
            newDestination = in.nextLine();

            System.out.print("Enter the type of Vacation(Single character code: ");
            validCharacterCode();

            while(newRating < MIN_RATING || newRating > MAX_RATING)
            {
                System.out.print("Enter the Rating(1-5): ");
                newRating = in.nextInt();
            }
            lastElement++;
            aDestination[lastElement] = new Destination(newDestination,newVacationType,newRating);

       }
       else
       {
            System.out.print("Cannot add new elements: ");
            System.out.println("List already has " + MAX_ELEMENT + " elements.");
       } 
   }

Answer 1

如果您决定使用Arrays.sort，则应遵循以下原则(包括使用 lambda 表达式的比较器函数的示例):

    public void add()
    {
        String newDestination;
        int newRating =-1;
        in = new Scanner(System.in);
        if((lastElement+1) < MAX_ELEMENT)    //MAX_ELEMENT =100
        {
            System.out.print("Enter the Name: ");
            newDestination = in.nextLine();

            System.out.print("Enter the type of Vacation(Single character code: ");
            String newVacationType = in.nextLine();

            while(newRating < MIN_RATING || newRating > MAX_RATING)
            {
                System.out.print("Enter the Rating(1-5): ");
                newRating = in.nextInt();
            }
            lastElement++;

            aDestination[lastElement] = new Destination(newDestination,newVacationType,newRating);
            Arrays.sort(aDestination, 0, lastElement, (o1, o2) -> o1.destination.compareTo(o2.destination));

       }
       else
       {
            System.out.print("Cannot add new elements: ");
            System.out.println("List already has " + MAX_ELEMENT + " elements.");
       } 
   }