java - 有没有办法循环使用断言来查找页面上所有损坏的图像

Question

我正在使用selenium webdriver + TestNG。如果可能的话帮助我解决以下问题:

搜索页面上所有损坏的图像，并在测试失败后在控制台中显示它们(使用断言)。

找到第一个损坏的图像后，以下测试失败，我需要测试来检查所有图像并在失败时显示结果:

public class BrokenImagesTest3_ {

@Test
public static void links() throws IOException, StaleElementReferenceException {

    System.setProperty("webdriver.chrome.driver", "/C: ...");
    WebDriver driver = new ChromeDriver();
    driver.manage().window().maximize();
    driver.get("https://some url");

    driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);

    //Find total Number of links on page and print In console.
    List<WebElement> total_images  = driver.findElements(By.tagName("img"));
    System.out.println("Total Number of images found on page = " + total_images .size());

    //for loop to open all links one by one to check response code.
    boolean isValid = false;
    for (int i = 0; i < total_images .size(); i++) {
        String image = total_images .get(i).getAttribute("src");


        if (image != null) {

            //Call getResponseCode function for each URL to check response code.
            isValid = getResponseCode(image);

            //Print message based on value of isValid which Is returned by getResponseCode function.
            if (isValid) {
                System.out.println("Valid image:" + image);
                System.out.println("----------XXXX-----------XXXX----------XXXX-----------XXXX----------");
                System.out.println();
            } else {
                System.out.println("Broken image ------> " + image);
                System.out.println("----------XXXX-----------XXXX----------XXXX-----------XXXX----------");
                System.out.println();
            }
        } else {
            //If <a> tag do not contain href attribute and value then print this message
            System.out.println("String null");
            System.out.println("----------XXXX-----------XXXX----------XXXX-----------XXXX----------");
            System.out.println();
            continue;
        }

    }
    driver.close();
}

//Function to get response code of link URL.
//Link URL Is valid If found response code = 200.
//Link URL Is Invalid If found response code = 404 or 505.
public static boolean getResponseCode(String chkurl) {
    boolean validResponse = false;
    try {
        //Get response code of image
        HttpClient client  = HttpClientBuilder.create().build();
        HttpGet request = new HttpGet(chkurl);
        HttpResponse response = client.execute(request);
        int resp_Code = response.getStatusLine().getStatusCode();
        System.out.println(resp_Code);
        Assert.assertEquals(resp_Code, 200);
        if (resp_Code != 200)  {
            validResponse = false;
        } else {
            validResponse = true;
        }
    } catch (Exception e) {

    }
    return validResponse;
    }
}

Answer 1

您的代码在第一次失败时停止的原因是因为您使用 Assert 使 resp_Code 等于 200。TestNG 将在第一次失败的断言时停止执行。

我会采取一些不同的做法。您可以使用 CSS 选择器通过 "img[src]" 仅查找包含 src 属性的图像，这样您就不必处理这种情况。当我查找损坏的图像时，我使用 naturalWidth 属性。如果图像损坏，则为 0。使用这两部分，代码看起来像......

List<WebElement> images = driver.findElements(By.cssSelector("img[src]"));
System.out.println("Total Number of images found on page = " + images.size());
int brokenImagesCount = 0;
for (WebElement image : images)
{
    if (isImageBroken(image))
    {
        brokenImagesCount++;
        System.out.println(image.getAttribute("outerHTML"));
    }
}
System.out.println("Count of broken images: " + brokenImagesCount);
Assert.assertEquals(brokenImagesCount, 0, "Count of broken images is 0");

然后添加这个功能

public boolean isImageBroken(WebElement image)
{
    return !image.getAttribute("naturalWidth").equals("0");
}

我只是写出损坏的图像。我更喜欢这种方法，因为它可以使日志保持干净。编写 image 会编写毫无用处的乱码，因此我将其更改为编写 externalHTML，即 IMG 标记的 HTML。