Python 序数排序

Question

早上好，我有一张表，我正在尝试返回位置(排名)学生的成绩。我已经到处寻找但没有找到更好的东西。我以为我可以通过排序来做到这一点，但事实并非如此。这是表格:

Name       Score    Position 

David      89        3rd
James      56        5th
Matt       72        4th
John       91        1st
Iva        56        5th
Anna       91        1st

我尝试编写此代码，但它没有处理重复项

score = [89, 56, 72, 91, 56,91]
order = sorted(list(set(score)), reverse=True)
position = []

for n in score:
     position.append(order.index(n) + 1)

print(position)

Answer 1

如果你愿意使用外部库，我只能推荐ranking :

import ranking

# Each player and their scores.
score_list = [
    ('David', 89),
    ('James', 56),
    ('Matt', 72),
    ('John', 91),
    ('Iva', 56),
    ('Anna', 91),
]

# Helper for accessing a score record's score, 
# defined here as we need it twice.
get_score = lambda pair: pair[1]

# Sort the scores in place; required by `ranking`.
score_list.sort(key=get_score, reverse=True)

# Define a format string; handy for formatting both the header and the scores.
format_str = "{player:10}   {score:<10}   {rank}"

# Print header.
print(format_str.format(player="Player", score="Score", rank="Position"))

# Rank and print.
for rank, (player, score) in ranking.Ranking(score_list, key=get_score, start=1):
    print(format_str.format(rank=rank, player=player, score=score))

输出

Player       Score        Position
John         91           1
Anna         91           1
David        89           3
Matt         72           4
James        56           5
Iva          56           5