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java - 如何处理org.xml.sax.SAXParseException?

转载 作者:行者123 更新时间:2023-12-02 02:57:35 25 4
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A 尝试从 https://www.boardgamegeek.com/xmlapi/boardgame/13/catan 解析 XML并获得语言依赖性最高票数的值。

这是代码:

public class DomParserDemo {

public static void main(String[] args) {

try {

DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
DocumentBuilder dbBuilder = dbFactory.newDocumentBuilder();
InputSource is = new InputSource(new StringReader("please paste XML from link");
Document doc = dbBuilder.parse(is);
doc.getDocumentElement().normalize();
System.out.println("Root element :" + doc.getDocumentElement().getNodeName());
NodeList nodeList = doc.getElementsByTagName("result") ;

String targetValue = "";
int maxNumVotes = 0;
for (int i = 0; i < nodeList.getLength(); i++) {
Element element = (Element) nodeList.item(i);
int numVotes = Integer.parseInt(element.getAttribute("numvotes"));
if (numVotes > maxNumVotes) {
maxNumVotes = numVotes;
targetValue = element.getAttribute("value");
}
}
System.out.println("Value: " + targetValue + " NumVotes: " + maxNumVotes);

}
catch (Exception e) {
e.printStackTrace();
}
}
}

输出:

[Fatal Error] :1:10703: The entity name must immediately follow the '&' in the entity reference.
org.xml.sax.SAXParseException; lineNumber: 1; columnNumber: 10703; The entity name must immediately follow the '&' in the entity reference.
at java.xml/com.sun.org.apache.xerces.internal.parsers.DOMParser.parse(DOMParser.java:261)
at java.xml/com.sun.org.apache.xerces.internal.jaxp.DocumentBuilderImpl.parse(DocumentBuilderImpl.java:339)
at DomParserDemo.main(DomParserDemo.java:17)

最佳答案

如果您在浏览器中打开 URL 并搜索 &,第一个命中将找到:

BGTG 115 - Spiel des Jahres,然后和;现在

& 是有效的实体引用。

如果继续搜索,第二次点击填充找到:

卡坦岛:城市与骑士

这是无效的 XML。 & 后面必须跟有名称和 ;。要在值中包含 &,必须将其转义为 &

简而言之,该 URL 返回的 XML 是无效,Java XML 解析器会告诉您这一点。

关于java - 如何处理org.xml.sax.SAXParseException?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/57067362/

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