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r - 基于字符串模糊匹配的连接数据框

转载 作者:行者123 更新时间:2023-12-02 02:56:36 43 4
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library(tidyverse)
library(fuzzyjoin)
df1 <- tibble(col1 = c("Apple Shipping", "Banana Shipping", "FedEX USA Ground",
"FedEx USA Commercial", "FedEx International"),
col2 = 1:5)
#> # A tibble: 5 x 2
#> col1 col2
#> <chr> <int>
#> 1 Apple Shipping 1
#> 2 Banana Shipping 2
#> 3 FedEX USA Ground 3
#> 4 FedEx USA Commercial 4
#> 5 FedEx International 5

df2 <- tibble(col3 = c("Banana", "FedEX USA"), col4 = c(700, 900))
#> # A tibble: 2 x 2
#> col3 col4
#> <chr> <dbl>
#> 1 Banana 700
#> 2 FedEX USA 900

上面显示了我正在使用的两个数据框。我想在 col1col3 上模糊连接它们,以得出类似于下面直接显示的内容。基本上规则是,“如果 col3 中的所有文本都在 col1 中的任何一个中,则将其视为匹配”。

#> # A tibble: 3 x 4
#> col1 col2 col3 col4
#> <chr> <int> <chr> <int>
#> 1 Banana Shipping 2 Banana 700
#> 2 FedEX USA Ground 3 FedEx USA 900
#> 3 FedEx USA Commercial 4 FedEx USA 900

This older SO question appears to offer the solution ,但在这种情况下似乎不太有效,我收到如下所示的错误:

df1 %>% regex_inner_join(df2, by = c(string = "col3"))
#> Error: All columns in a tibble must be 1d or 2d objects:
#> * Column `col` is NULL
#> Run `rlang::last_error()` to see where the error occurred.

library(stringr)
df1 %>% fuzzy_inner_join(df2, by = c("string" = "col3"), match_fun = str_detect)
#> Error: All columns in a tibble must be 1d or 2d objects:
#> * Column `col` is NULL
#> Run `rlang::last_error()` to see where the error occurred.

如何使用 R 执行此模糊连接?

最佳答案

也许这就是您正在寻找的东西?

library(dplyr)
library(fuzzyjoin)
library(stringr)
df1 %>% fuzzy_inner_join(df2,by=c("col1" = "col3"),match_fun = str_detect)
## A tibble: 2 x 4
# col1 col2 col3 col4
# <chr> <int> <chr> <dbl>
#1 Banana Shipping 2 Banana 700
#2 FedEX USA Ground 3 FedEX USA 900

如果您想忽略大小写,您可以定义自己的str_detect

my_str_detect <- function(x,y){str_detect(x,regex(y, ignore_case = TRUE))}
df1 %>% fuzzy_inner_join(df2,by=c("col1" = "col3"),match_fun = my_str_detect)
## A tibble: 3 x 4
# col1 col2 col3 col4
# <chr> <int> <chr> <dbl>
#1 Banana Shipping 2 Banana 700
#2 FedEX USA Ground 3 FedEX USA 900
#3 FedEx USA Commercial 4 FedEX USA 900

要获得奖励积分,您可以使用 this question 中的 agrepl .

您可以修改 max.distance = 参数,并可能添加 cost =。请参阅 help(agrepl) 了解更多信息。

my_match_fun <- Vectorize(function(x,y) agrepl(x, y, ignore.case=TRUE, max.distance = 0.7, useBytes = TRUE))
df1 %>% fuzzy_inner_join(df2,by=c("col1" = "col3"),match_fun = my_match_fun)
## A tibble: 4 x 4
# col1 col2 col3 col4
# <chr> <int> <chr> <dbl>
#1 Banana Shipping 2 Banana 700
#2 FedEX USA Ground 3 FedEX USA 900
#3 FedEx USA Commercial 4 FedEX USA 900
#4 FedEx International 5 FedEX USA 900

关于r - 基于字符串模糊匹配的连接数据框,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/60993676/

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