Python-如何比较字符串中两个列表的内容

Question

我需要比较列表“present”的所有项目都在字符串“line”中，而列表“absent”的所有元素都不在字符串“line”中

所以，有 2 个列表

present = ['SYN', 'ACK']
absent = ['RST', 'FIN']

还有一个包含此处所有 TCP 标志的文件:https://github.com/robcowart/elastiflow/blob/master/logstash/elastiflow/dictionaries/tcp_flags.yml

"...
"12": RST-PSH
"13": FIN-RST-PSH
"14": SYN-RST-PSH
"15": FIN-SYN-RST-PSH
"16": ACK
"17": FIN-ACK
"18": SYN-ACK
"19": FIN-SYN-ACK
"20": RST-ACK
"21": FIN-RST-ACK
"22": SYN-RST-ACK
"23": FIN-SYN-RST-ACK
..."

如果该行中存在所有“present”元素并且该行中不存在所有“absent”元素，我将逐行读取该文件，然后打印该行

我该怎么做？我想象递归或理解，但我找不到方法。谢谢

Answer 1

for line in csv_reader:
    # parse the line and store the flags into a list
    # flags = line.split...

    # the logic to check for present and absent
    is_present = all(elem in flags for elem in present)
    is_absent = not any(elem in flags for elem in absent)
    if is_present and is_absent:
        print(line)