java - 如何获取我要使用多部分上传的文件的名称

Question

我想获取我正在上传的文件的名称。目的是获取文件的完整路径(包括带扩展名的文件名)。jsp:-

<form action="go" method="post" enctype="multipart/form-data">  
        Select File:<input type="file" name="fname"/><br/>  
        <input type="submit" value="upload"/>  

 </form>  

servlet:-

        protected void processRequest(HttpServletRequest request,  HttpServletResponse response)
        throws ServletException, IOException {
       response.setContentType("text/html");  
      PrintWriter out = response.getWriter();  
      String filename=request.getParameter("fname"); //unable to get fname
MultipartRequest m=new MultipartRequest(request,"d:/new");
String filePath="d:/new".concat(filename);
out.print("successfully uploaded");   
out.print(filePath);
}

Answer 1

A.Plain Servlet 解决方案:

<强>1。获取javax.servlet.http.Part来自 HttpServletRequest

   String fileName = null;
        //Get all the parts from request and write it to the file on server
        for (Part part : request.getParts()) {
            fileName = getFileName(part);
          }

<强>2。从零件中获取文件名

   /**
     * Utility method to get file name from HTTP header content-disposition
     */
    private String getFileName(Part part) {
        String contentDisp = part.getHeader("content-disposition");
        System.out.println("content-disposition header= "+contentDisp);
        String[] tokens = contentDisp.split(";");
        for (String token : tokens) {
            if (token.trim().startsWith("filename")) {
                return token.substring(token.indexOf("=") + 2, token.length()-1);
            }
        }
        return "";
    }

================================================== ====

基于B.Spring的解决方案:

使用spring，当你上传文件时，request是org.springframework.web.multipart.MultipartHttpServletRequest的实例

您可以从 MultipartHttpServletRequest 获取上传的文件名，如下所示。

   // cast request
    MultipartHttpServletRequest multipartRequest = (MultipartHttpServletRequest) request;
    // get filenames as iterator

    Iterator<String> iterator = multipartRequest.getFileNames();

    while (iterator.hasNext()) {
        String uploadedFileName = (String) iterator.next();

    }