java - 如何处理包含正斜杠的请求？

Question

我的 URL 请求是 http://localhost:8080/login/verify/212,32,/cntv5tag07rmy791wbme7xa8x,/SSNZclzqhhH7v6uHIkUsIcPusKo=

我需要获取以下部分:**212,32,/cntv5tag07rmy791wbme7xa8x,/SSNZclzqhhH7v6uHIkUsIcPusKo=**。

以下代码不起作用:

@RequestMapping(value = "/login/verify/{request:.+}", method = RequestMethod.POST, produces = {"application/json;charset=UTF-8"})
    public ResponseEntity verifyLogin(@PathVariable(value = "request") String request)
            throws InvalidSignatureException
    {
}

错误:HTTP 状态 404。

Spring 无法处理此请求。

Answer 1

要将 uri 与斜杠匹配，请使用双 *

@RequestMapping(value = "/login/verify/**",

然后，在正文中获取值时，您将使用

String str = (String) request.getAttribute(HandlerMapping.PATH_WITHIN_HANDLER_MAPPING_ATTRIBUTE)

示例代码:

@RequestMapping(value = "/login/verify/**", method = RequestMethod.POST, produces = {"application/json;charset=UTF-8"}) 
public ResponseEntity verifyLogin(HttpServletRequest httpServletRequest) throws InvalidSignatureException {
    String str = (String) request.getAttribute( HandlerMapping.PATH_WITHIN_HANDLER_MAPPING_ATTRIBUTE)
}