java - 如何查找字符串中字符之间的最长距离

Question

public class LongestAlphabetDistance {

    public int longDistance(String str, String a) {
        str = "this is my greatest achievement in the world";
        a = "i";
        int count =0;
        // code logic for longest difference
        return count;
    }
}

我想首先获得“这是我在世界上最伟大的成就”距离黑白a = i 和最后一个 i t=1,h=2,i=3,s=4, 空间不应比 i=5,s =6,m=7,y=8,g=9 就像最后一个i“in”i=27所以首先i=3 最后一个i=27 所以最长的距离b/w 24 请为此编写一个代码

Answer 1

public class LongestAlphabetDistance {

    public int longDistance(String str, String a) {
        str = "this is my greatest achivement in the world";
        a = "i";
        str = str.replaceAll("\\s", "");
        char[] chArray = str.toCharArray();
        ArrayList<Integer> inArray = new ArrayList<>();

        for(int i =0;i<chArray.length;i++) {
            if(chArray[i] == a.charAt(0) ) {
                inArray.add(i+1);
            }
        }

        return inArray.get(inArray.size()-1)-inArray.get(0); // 24 
    }
}