java - 如何删除动态添加的节点

Question

我在 for 循环中生成了四个 HBox。每个HBox都有1个“删除按钮”。如何定位一个删除按钮来仅删除相应的HBox？我将所有 HBox 添加到名为 questionField 的 VBox 中。

现在我正在使用:

private void removeAnswer() {
    this.questionField.getChildren().removeAll(hBox);
}

但这会删除所有 4 个 HBox。我需要一些东西能够单独定位特定的 HBox。

这是循环:

newAnswerTextField = new TextField[4];
answerCheckbox = new CheckBox[4];
ToggleGroup answerToggleGroup = new ToggleGroup();
radioButtonAnswer = new RadioButton[4];
hBox = new HBox[4];

for(int i = 0; i < 4; i++){
    hBox[i] = new HBox();
    Button deleteButton = new Button("X");
    deleteButton.setOnAction(e -> {
        removeAnswer();
    });

    newAnswerTextField[i] = new TextField();
    newAnswerTextField[i].setText("Fråga " + questionNumber + " svar " + answerNumber++);
    hBox[i].getChildren().addAll(deleteButton, newAnswerTextField[i]);

    radioButtonAnswer[i] = new RadioButton("Rätt svar");
    radioButtonAnswer[i].setToggleGroup(answerToggleGroup);
    hBox[i].getChildren().add(radioButtonAnswer[i]);

    questionField.getChildren().add(hBox[i]);
}

Answer 1

您可以简单地将要删除的 HBox 作为参数传递给您的 removeAnswer 方法:

private void removeAnswer(Node answer) {
    this.questionField.getChildren().remove(answer);
}

for(int i = 0; i < 4; i++) {
    final HBox answer = new HBox();
    hBox[i] = answer;
    Button deleteButton = new Button("X");
    deleteButton.setOnAction(e -> {
       removeAnswer(answer);
    });

    ...
}