java - 每次应用程序运行时，listView 项目都会重复并变得越来越多

Question

我正在为Android实现一个示例应用程序，在 ListView 中我不使用 View 持有者，所以我无法从其他答案中得到答案。每次运行应用程序时，我的 ListView 项目都会重复并变得更多，除非我从模拟器中卸载应用程序。这是我的代码，在第一个类中我声明 ListView 并设置适配器，下一个类是自定义适配器(我删除了不必要的函数):

public class CrimeListFragment extends Fragment {
    private ListView crimesListView;
    private CrimeAdapter adapter;

    @Override
    public void onCreate( Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setHasOptionsMenu(true);
    }

    @Override
    public View onCreateView( LayoutInflater inflater,  ViewGroup container,  Bundle savedInstanceState) {
       View CrimesList=inflater.inflate(R.layout.fragment_crime_list,container,false);
       crimesListView=(ListView) CrimesList.findViewById(R.id.crimesList);
       adapter=new CrimeAdapter(inflater.getContext(),R.layout.list_item_crime,CrimeLab.get(inflater.getContext()).getCrimes());
       crimesListView.setAdapter(adapter);


}
public class CrimeAdapter extends ArrayAdapter {
    Context _context;
    List<Crime> _crimes;
    static Crime currentCrime;
    public CrimeAdapter( Context context, int resource,  List crimes) {
        super(context, resource, crimes);
        _context=context;
        _crimes=crimes;
    }


    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View _convertView = convertView; // re-use an existing view, if one is available
        if (_convertView == null)
            _convertView= ((Activity)_context).getLayoutInflater().inflate(R.layout.list_item_crime,null);

         currentCrime=_crimes.get(position);
          ((TextView)_convertView.findViewById(R.id.crimeTitleText)).setText(currentCrime.getTitle().toString());
        ((TextView)_convertView.findViewById(R.id.crimeDateText)).setText(currentCrime.getCrimeDate().toString());
        ((ImageView)_convertView.findViewById(R.id.crimeImageSolved)).setVisibility(currentCrime.getSolved() ? View.VISIBLE : View.GONE);


       return _convertView;
    }
    public void setCrimes(List<Crime> crimes){
        _crimes=crimes;
    }
}

Answer 1

改变

_convertView= ((Activity)_context).getLayoutInflater().inflate(R.layout.list_item_crime,null);

至

_convertView = LayoutInflater.from(getContext()).inflate(R.layout.list_item_crime, parent, false);