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mysql - 加入后在数据库中填充以下日期的值

转载 作者:行者123 更新时间:2023-12-02 02:42:09 24 4
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我实际上需要用存档中的下一个可用数据填充不存在的条目。

背景:所以我有一个记录,它每月归档每个状态。但是,它只会在有新值时更新,并将旧值保存到上个月。使用 MySQL v8。

如何用下一个填写时间段的相同ID的数据填写表格中的缺失值?

archivesDate='2019-08-01' 中的所有内容都故意包含 NULL 数据。这意味着下个月是数据开始的时间。

中间3个archivesDate='2019-09-01'需要填写以后相同statusID的下一条数据;在本例中,它来自 archivesDate='2019-10-01'。这可能是 10 月、11 月,或 future 的任何时间。它只需要填写下一个值。

我试过的,但这只是 ID 上的一个连接,这就是为什么 September 显示为 NULL

SELECT
al.statusID,
sa.statusDate,
sa.statusFlagsID,
sa.statusPrice,
al.archivesDate
FROM (
SELECT
sid.statusID AS statusID,
a.archivesID AS archivesID,
a.archivesDate AS archivesDate
FROM (
SELECT
DISTINCT statusID
FROM statusArchive) sid
CROSS JOIN archives a) al
LEFT JOIN statusArchive sa
ON sa.statusID = al.statusID --This needs to be changed to get next value in cases where there is no value available
AND sa.archivesID = al.archivesID --This needs to be changed to get next value in cases where there is no value available
ORDER BY al.archivesDate, al.statusID

当前输出:

statusID statusDate statusFlagsID statusPrice archivesDate
1 2019-08-01
2 2019-08-01
3 2019-08-01
1 2019-09-01
2 2019-09-01
3 2019-09-01
1 2018-10-01 1 37 2019-10-01
2 2018-11-05 1 90 2019-10-01
3 2019-01-01 1 3 2019-10-01

期望的输出:

statusID statusDate statusFlagsID statusPrice archivesDate
1 2019-08-01
2 2019-08-01
3 2019-08-01
1 2018-10-01 1 37 2019-09-01
2 2018-11-05 1 90 2019-09-01
3 2019-01-01 1 3 2019-09-01
1 2018-10-01 1 37 2019-10-01
2 2018-11-05 1 90 2019-10-01
3 2019-01-01 1 3 2019-10-01

编辑:添加了模型源表(包含提供上述内容的所有信息):

源数据

文件

archivesID       archivesDate
1 2019-08-01
2 2019-09-01
3 2019-10-01

STATUSARCHIVE(将 s 替换为以下列名称中的状态,SO 格式问题抱歉)

注意:archivesID=2

中缺少条目
sArchiveID  sID  sFlagsID  sPrice  sDate       archivesID
1 1 NULL NULL NULL 1
2 2 NULL NULL NULL 1
3 3 NULL NULL NULL 1
4 1 1 37 2018-10-01 3
5 2 1 90 2018-11-05 3
6 3 1 3 2019-01-01 3

DB-Fiddle here以及创建数据源的 SQL:

CREATE TEMPORARY TABLE archives (
archivesID INT,
archivesDate DATE
);
INSERT INTO archives (archivesID, archivesDate) VALUES (1, '2019-08-01');
INSERT INTO archives (archivesID, archivesDate) VALUES (2, '2019-09-01');
INSERT INTO archives (archivesID, archivesDate) VALUES (3, '2019-10-01');

CREATE TEMPORARY TABLE statusArchive (
statusArchiveID INT,
statusID INT,
statusFlagsID INT,
statusPrice DECIMAL,
statusDate DATE,
archivesID INT
);
INSERT INTO statusArchive (statusArchiveID, statusID, statusFlagsID, statusPrice, statusDate, archivesID)
VALUES (1, 1, NULL, NULL, NULL, 1);
INSERT INTO statusArchive (statusArchiveID, statusID, statusFlagsID, statusPrice, statusDate, archivesID)
VALUES (2, 2, NULL, NULL, NULL, 1);
INSERT INTO statusArchive (statusArchiveID, statusID, statusFlagsID, statusPrice, statusDate, archivesID)
VALUES (3, 3, NULL, NULL, NULL, 1);
INSERT INTO statusArchive (statusArchiveID, statusID, statusFlagsID, statusPrice, statusDate, archivesID)
VALUES (4, 1, 1, 37, '2018-10-01', 3);
INSERT INTO statusArchive (statusArchiveID, statusID, statusFlagsID, statusPrice, statusDate, archivesID)
VALUES (5, 2, 1, 90, '2018-11-05', 3);
INSERT INTO statusArchive (statusArchiveID, statusID, statusFlagsID, statusPrice, statusDate, archivesID)
VALUES (6, 3, 1, 3, '2019-01-01', 3);

最佳答案

快速修复:将您的评论翻译成代码。

AND sa.archivesID = al.archivesID -- This needs to be changed to get next value
-- in cases where there is no value available

成为

AND sa.archivesID = (
SELECT MIN(x.archivesID)
FROM statusArchive x
WHERE x.statusID = al.statusID
AND x.archivesID >= al.archivesID
)

完整查询:

SELECT
al.statusID,
sa.statusDate,
sa.statusFlagsID,
sa.statusPrice,
al.archivesDate
FROM (
SELECT
sid.statusID AS statusID,
a.archivesID AS archivesID,
a.archivesDate AS archivesDate
FROM (SELECT DISTINCT statusID FROM statusArchive) sid
CROSS JOIN archives a
) al
LEFT JOIN statusArchive sa
ON sa.statusID = al.statusID
AND sa.archivesID = (
SELECT MIN(x.archivesID)
FROM statusArchive x
WHERE x.statusID = al.statusID
AND x.archivesID >= al.archivesID
)
ORDER BY al.archivesDate, al.statusID

结果:

| statusID | archivesDate | statusDate | statusFlagsID | statusPrice |
| -------- | ------------ | ---------- | ------------- | ----------- |
| 1 | 2019-08-01 | | | |
| 2 | 2019-08-01 | | | |
| 3 | 2019-08-01 | | | |
| 1 | 2019-09-01 | 2018-10-01 | 1 | 37 |
| 2 | 2019-09-01 | 2018-11-05 | 1 | 90 |
| 3 | 2019-09-01 | 2019-01-01 | 1 | 3 |
| 1 | 2019-10-01 | 2018-10-01 | 1 | 37 |
| 2 | 2019-10-01 | 2018-11-05 | 1 | 90 |
| 3 | 2019-10-01 | 2019-01-01 | 1 | 3 |

View on DB Fiddle

注意:您应该在 statusArchive(statusID, archivesID [other columns]) 上有一个索引。

以下(较短的)查询也适用于给定的示例数据:

select 
s.statusID,
s.statusDate,
s.statusFlagsID,
s.statusPrice,
a.archivesDate
from archives a
left join statusArchive s
on s.archivesID = (
select min(x.archivesID)
from statusArchive x
where x.archivesID >= a.archivesID
)
order by a.archivesDate, s.statusID;

对于此查询,您应该在 statusArchive(archivesID) 上有一个索引。

结果:

| statusID | statusDate | statusFlagsID | statusPrice | archivesDate |
| -------- | ---------- | ------------- | ----------- | ------------ |
| 1 | | | | 2019-08-01 |
| 2 | | | | 2019-08-01 |
| 3 | | | | 2019-08-01 |
| 1 | 2018-10-01 | 1 | 37 | 2019-09-01 |
| 2 | 2018-11-05 | 1 | 90 | 2019-09-01 |
| 3 | 2019-01-01 | 1 | 3 | 2019-09-01 |
| 1 | 2018-10-01 | 1 | 37 | 2019-10-01 |
| 2 | 2018-11-05 | 1 | 90 | 2019-10-01 |
| 3 | 2019-01-01 | 1 | 3 | 2019-10-01 |

View on DB Fiddle

但是 - 我不知道这是否会在任何可能的数据集上返回所需的结果,因为我只能从您的示例数据和结果中猜测确切的要求。

更新

如果您需要按相应的 archivesDate 排序的下一行,您将需要一个 ORDER BY ... LIMIT 1 子查询:

SELECT
al.statusID,
sa.statusDate,
sa.statusFlagsID,
sa.statusPrice,
al.archivesDate
FROM (
SELECT
sid.statusID AS statusID,
a.archivesID AS archivesID,
a.archivesDate AS archivesDate
FROM (SELECT DISTINCT statusID FROM statusArchive) sid
CROSS JOIN archives a
) al
LEFT JOIN statusArchive sa
ON sa.statusID = al.statusID
AND sa.archivesID = (
SELECT x.archivesID
FROM statusArchive x
JOIN archives y ON y.archivesID = x.archivesID
WHERE x.statusID = al.statusID
AND y.archivesDate >= al.archivesDate
ORDER BY y.archivesDate ASC
LIMIT 1
)
ORDER BY al.archivesDate, al.statusID;

确保你有索引

  • statusArchive(statusID [, other columns]) for x.statusID = al.statusID 以及 SELECT DISTINCT statusID FROM statusArchive
  • archives(archivesID, archivesDate, [, other columns]) 对于条件 y.archivesID = x.archivesIDy.archivesDate >= al。 archivesDate 和 ORDER BY 子句 y.archivesDate ASC

关于mysql - 加入后在数据库中填充以下日期的值,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/58832166/

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