c# - 如何从一个方法返回多个值？

Question

在以下代码中，我希望 y 返回多个值，但程序仅返回最后一个值。

public int runDraw()
{
    for (int j = 1; j <= numberofDraws; j++)
    {
        ...
        if (even_count > odd_count)
        {
            Console.WriteLine("The result of {0} draw is Even.", j);
            y = 1;
        }
        else if (even_count < odd_count)
        {
            Console.WriteLine("The result of {0} draw is Odd.", j);
            y = 2;
        }
        else
        {
            Console.WriteLine("The result of {0} draw is Draw.", j);
            y = 3;
        }
    }
    return y;
}

Answer 1

一种选择是返回 int 枚举，因为单个 int 不能直接表示多个值。这是一个使用 yield return 的示例，如果您需要的话，它只会继续到下一个值。

    public IEnumerable<int> runDraw()
    {
        for (int j = 1; j <= numberofDraws; j++)
        {
        ...
            if (even_count > odd_count)
            {
                Console.WriteLine("The result of {0} draw is Even.", j);
                yield return 1;
            }
            else if (even_count < odd_count)
            {
                Console.WriteLine("The result of {0} draw is Odd.", j);
                yield return 2;
            }
            else
            {
                Console.WriteLine("The result of {0} draw is Draw.", j);
                yield return 3;
            }
        }
        yield return y;
        // What you do here really depends on your unshared logic
        // You might return 0 or throw an exception if this is invalid
    }

然后您可以迭代地访问这些值，例如使用 foreach 循环:

foreach (int j in runDraw())
{
    Console.WriteLine(j);
}