java - 我的java代码没有错误但停在nextInt

Question

我正在编写一个 Java 代码，它将在 Chrome 或 Firefox 中运行一个简单的自动化场景 - 具体取决于用户的输入。没有下划线错误，但程序卡在 nextInt 行(在调试器中看到)，并且没有输出。有人可以帮忙吗？谢谢!

package com.selenium;

import java.util.Scanner;

import org.openqa.selenium.By;
import org.openqa.selenium.Keys;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.chrome.ChromeDriver;
import org.openqa.selenium.firefox.FirefoxDriver;

public class Main {

    public static void main(String[] args) throws InterruptedException {
        // environment variable
        System.setProperty("webdriver.chrome.driver", "C:\\Automation\\libs\\Drivers\\chromedriver.exe");
        //WebDriver chromeDriver = new ChromeDriver();
        System.setProperty("webdriver.gecko.driver", "C:\\Automation\\libs\\Drivers\\geckodriver.exe");
        WebDriver driver = null;

        Scanner scanner = new Scanner(System.in);
        int option = scanner.nextInt();
        System.out.println("Please enter 1 for Chrome or 2 for Firefox " + option);
        if (option == 1)
        {
            WebDriver driver1= new FirefoxDriver();
        }
        else if 
        (option == 2)
        {
            WebDriver driver2 = new ChromeDriver();
        }
        else 
            System.out.println("Please enter a correct number " + option);

        String baseURL = "https://login.salesforce.com/?locale=eu";

        driver.get(baseURL);

        WebElement userName = driver.findElement(By.id("username"));
        userName.sendKeys("Yan");

        WebElement password = driver.findElement(By.id("password"));
        password.sendKeys("123456");

        WebElement rememberCheckbox = driver.findElement(By.id("rememberUn"));
        rememberCheckbox.click();

        WebElement bLogin = driver.findElement(By.id("Login"));
        bLogin.click();

        }

    }

Answer 1

将 System.out 放在 scanner.nextInt() 之前

Scanner scanner = new Scanner(System.in);
System.out.println("Please enter 1 for Chrome or 2 for Firefox " + option);
int option = scanner.nextInt();

然后，当要求您输入数字时，在键盘上键入 1 或 2。