java - java SocketServer 是如何工作的？

Question

我是java新手，我无法理解void go()方法的while循环部分。accept()方法等待客户端请求连接到服务器，那么为什么像Print writer等其他语句，没有被执行？

其他语句是否在 while 循环中等待accept()方法运行？

 import java.io.*;
  import java.net.*;
 import java.util.*;


 public class VerySimpleChatServer
 {
ArrayList clientOutputStreams;

public class ClientHandler implements Runnable {
    BufferedReader reader;
    Socket sock;

    public ClientHandler(Socket clientSOcket) {
        try {
            sock = clientSOcket;
            InputStreamReader isReader = new InputStreamReader(sock.getInputStream());
            reader = new BufferedReader(isReader);

        } catch (Exception ex) { ex.printStackTrace(); }
    }

    public void run() {
        String message;
        try {
            while ((message = reader.readLine()) != null) {
                System.out.println("read " + message);
                tellEveryone(message);
            }
        } catch (Exception ex) { ex.printStackTrace(); }
    }
}

public static void main(String[] args) {
    new VerySimpleChatServer().go();
}

public void go() {
    clientOutputStreams = new ArrayList();
    try {
        ServerSocket serverSock = new ServerSocket(5000);
        while(true) {
            Socket clientSocket = serverSock.accept();
            PrintWriter writer = new PrintWriter(clientSocket.getOutputStream());
            clientOutputStreams.add(writer);

            Thread t = new Thread(new ClientHandler(clientSocket));
            t.start();
            System.out.println("got a connection");
        }
    } catch (Exception ex) { ex.printStackTrace(); }
}

public void tellEveryone(String message) {
    Iterator it = clientOutputStreams.iterator();
    while (it.hasNext()) {
        try {
            PrintWriter writer = (PrintWriter) it.next();
            writer.println(message);
            writer.flush();
        } catch (Exception ex) { ex.printStackTrace(); }
    }
}
}

没有任何线索，请帮忙

Answer 1

该接受方法不仅仅等待。

它阻止。仅当该方法返回时才会继续执行! “执行流程”就此停止 - 在该方法调用返回之前，以下语句无关紧要。

这就是全部内容了。