json - Spring 2.5 和 Json(Spring Json View )

Question

有没有人试过Spring Json View教程？

我按照该教程进行操作，但在访问 hello.json 时出现 404 错误。

我刚开始使用 Spring 编写 Java 应用程序，可能是我的配置文件有问题吗？

我的项目名称是jsonapp

web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
    id="WebApp_ID" version="2.5">
    <display-name>jsonapp</display-name>
    <servlet>
        <servlet-name>jsonapp</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>jsonapp</servlet-name>
        <url-pattern>*.htm</url-pattern>
    </servlet-mapping>

</web-app>

jsonapp-servlet.xml

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
        http://www.springframework.org/schema/beans/spring-beans-2.5.xsd
        http://www.springframework.org/schema/context
        http://www.springframework.org/schema/context/spring-context-2.5.xsd">

    <context:component-scan base-package="com.tutorial.json.web" />

    <bean
        class="org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping" />
    <bean
        class="org.springframework.web.servlet.mvc.annotation.AnnotationMethodHandlerAdapter" />

    <bean name="viewResolver" 
        class="org.springframework.web.servlet.view.XmlViewResolver" />

</beans>

view.xml

<beans xmlns="http://www.springframework.org/schema/beans"
    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xsi:schemaLocation="http://www.springframework.org/schema/beans
    http://www.springframework.org/schema/beans/spring-beans-2.5.xsd">

    <bean name="jsonView" class="org.springframework.web.servlet.view.json.JsonView"/>
</beans>

HelloController.java

package com.tutorial.json.web;

import java.util.HashMap;
import java.util.Map;

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RequestMethod;
import org.springframework.web.servlet.ModelAndView;

@Controller
@RequestMapping("/hello.json")
public class HelloController {
    @RequestMapping(method = RequestMethod.GET)
    public ModelAndView hello() {
        Map<String, String> model = new HashMap<String, String>();
        model.put("firstname", "Peter");
        model.put("secondname", "Schmitt");

        return new ModelAndView("jsonView", model);
    }
}

谢谢你的帮助

Answer 1

<url-pattern>在你的 web.xml 中映射到 *.htm而不是 *.json