ios - iOS 应用程序的 Firebase 3.7.0 上的链接错误

Question

我尝试在 iOS 应用程序中使用 Firebase SDK 3.7.0，但出现链接错误。

我已按照 README.md 中描述的步骤进行操作，该文件包含在从 https://firebase.google.com/docs/ios/setup 下载的框架 SDK 中，关于不使用 CocoaPods 的集成部分。

链接时出现以下错误:

Undefined symbols for architecture armv7:
  "_sqlite3_bind_double", referenced from:
      ___48-[FIRASqliteStore bindValues:toStatement:error:]_block_invoke in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_bind_null", referenced from:
      ___48-[FIRASqliteStore bindValues:toStatement:error:]_block_invoke in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_column_type", referenced from:
      -[FIRASqliteStore valueAtColumn:forStatement:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_column_double", referenced from:
      -[FIRASqliteStore valueAtColumn:forStatement:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_open_v2", referenced from:
      -[FIRASqliteStore openAndValidateDatabase:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_clear_bindings", referenced from:
      -[FIRASqliteStore cleanUpStatement:forQuery:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
      -[FIRASqliteStore bindValues:toStatement:error:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_column_count", referenced from:
      -[FIRASqliteStore recordsForQuery:parameterValues:error:withFilter:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
      -[FIRASqliteStore validateDatabaseWithError:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_OBJC_CLASS_$_SSReadingList", referenced from:
      objc-class-ref in GoogleSignIn(please_link_SafariServices.framework_.o)
  "_OBJC_CLASS_$_MFMessageComposeViewController", referenced from:
      objc-class-ref in FirebaseInvites(GINInviteController_af66380ba390cf14b066932397806d20.o)
      objc-class-ref in FirebaseInvites(GPPACLSearchViewController_3fc71921176f5b855c444ab9ce9260c7.o)
      objc-class-ref in FirebaseInvites(GINInviteScrollView_5b90efc8e1a69f9dfe581b021e7f869b.o)
  "_OBJC_CLASS_$_CMMotionManager", referenced from:
      objc-class-ref in FirebaseDynamicLinks(GPPSpamSignal_a0a54565a3243ede865cc9b2724bc7a8.o)
  "_sqlite3_column_bytes", referenced from:
      -[FIRMessagingRmq2PersistentStore scanOutgoingRmqMessagesWithHandler:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
      -[FIRASqliteStore valueAtColumn:forStatement:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_reset", referenced from:
      -[FIRASqliteStore cleanUpStatement:forQuery:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_changes", referenced from:
      -[FIRMessagingRmq2PersistentStore deleteMessagesFromTable:withRmqIds:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
      -[FIRMessagingRmq2PersistentStore deleteExpiredOrFinishedSyncMessages:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
      -[FIRASqliteStore deleteRecordsFromTableWithName:condition:parameterValues:error:] in FirebaseAnalytics(FIRASqliteStore_2e8a0f466f3be880241569cb2066f73b.o)
  "_sqlite3_errmsg", referenced from:
      -[FIRMessagingRmq2PersistentStore saveMessageWithRmqId:tag:data:error:] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)
      -[FIRMessagingRmq2PersistentStore lastErrorMessage] in FirebaseMessaging(FIRMessagingRmq2PersistentStore_66612bb0cdda59e6a475d66db9ec25d4.o)

XCode版本为7.0.1

Answer 1

您需要添加此框架，因为您没有使用 Pod

libicucore.tbd

CFNetwork.framework

Security.framework

SystemConfiguration.framework

libc++.tbd

libsqlite3.tbd

对于 2020 年，如果您遇到以下令人恼火的错误:

_OBJC_CLASS_$_SKPaymentQueue
_OBJC_CLASS_$_SKProductsRequest

然后，另外添加StoreKit