java - 为什么空格后面的所有内容都不打印？

Question

我使用 acm 库创建了一个简单的程序，该程序接受用户输入的字符串并以莫尔斯电码打印出来。这是程序:

import acm.program.*;

public class morse extends Program{
    public void run(){

        String[] alphabet = {"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z"};
        String[] morse = {".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};
        String word = readLine("Give the word(s) to transcribe: ").toUpperCase();
        println("Morse: ");
        int j = 0;
        for(int i = 0; i < word.length(); i++){
            int k = 0;
            boolean flag = true;
            if(Character.toString(word.charAt(j)).equals(" ")){
                println();
            }else {
                while(!Character.toString(word.charAt(j)).equals(alphabet[k])){
                    if(k < 25){
                        k += 1;
                    }else{
                        println("Letter was not found.");
                        flag = false;
                        break;
                    }
                }
                if(flag){
                    println(morse[k] + " ");
                }
            j += 1;
            }   
        }
    }
}

但是，每次字符串包含空格时，空格后面的所有内容都不会打印。我真的找不到这背后的原因。任何人都可以帮助我，甚至给我指出某个地方吗？谢谢

(空格后面的字母全部打印为空格)

Answer 1

我不知道为什么你在for循环中定义了i但从未使用它。您的主要问题是，当您遇到空格时，您不会增加 j 。我认为你有两个选择:

• 在 if 内调用 println(); 后递增 j
• 完全删除j，只需在以前使用过j的地方使用i(可能是更好的主意)

<小时/>

对您的代码的一般建议:您正在执行太多奇怪的字符和字符串逻辑。你可以这样做

• 放下字母
• 以与当前相同的方式从 String 获取 char
• 从中减去'A'
• 使用生成的char作为索引来访问morse数组
• 删除 k 和整个 while 循环。