Symfony Autowiring 独白 channel

Question

关注此documentation ，我可以创建许多 channel ，这些 channel 将创建具有以下名称 monolog.logger.<channel_name> 的服务

如何通过 DI 注入(inject)和 Autowiring 将这些服务注入(inject)到我的服务中？

class FooService
{
    public function __construct(LoggerInterface $loggerInterface) {  }
}

Yaml

#existing
foo_service:
    class: AppBundle\Services\FooService
    arguments: ["@monolog.logger.barchannel"]
# what I want to do
foo_service:
    autowire: true # how to inject @monolog.logger.barchannel ? 

Answer 1

Starting from MonologBundle 3.5 you can autowire different Monolog channels by type-hinting your service arguments with the following syntax: Psr\Log\LoggerInterface $<channel>Logger. For example, to inject the service related to the app logger channel use this:

public function __construct(LoggerInterface $appLogger)
{
   $this->logger = $appLogger;
}

https://symfony.com/doc/current/logging/channels_handlers.html#monolog-autowire-channels