java - 数组大小不确定的写入循环

Question

下面的代码工作正常。

private int[] list = new int[]{ 3, 5, 10};
private int[] temp = new int[list.length];

public void Generate()
{
    for (int a=0;a<list[0];a++)
    {
        temp[0] = a;
        for (int b=0;b<list[1];b++)
        {
            temp[1] = b;
            for (int c=0;c<list[2];c++)
            {
                temp[2] = c;
                int[] asd = temp;
            }
        }
    }
}

但是如果我更改列表数组长度，我必须在内部添加一个 for 循环。如何为任意大小的列表数组编写一种方法？例如:

private int[] list = new int[]{ 2, 5, 12,18};

代码不起作用!

Answer 1

我不是 100% 确定你的函数应该产生什么结果，但如果你想在单个函数中得到与你的代码等效的结果，那么它看起来像这样(假设 C# 作为语言):

private int[] list = new int {3, 5, 10};

public void Generate()
{
    List<string> toPrint = new List<string>();
    string num_string = string.Empty;    
    string base_string = string.Empty;
    for(int i=list.length; i>-1; i--)
    {
        num_string = num_string + list[i].ToString();
        base_string = base_string +'0';
    }
    lastnumber = Int16.parse(num_string[list.length - 1]);
    int string_length = base_string.length;
    bool running = true;
    while(running)
    {   
        bool finished = true;
        for(int incre=0; incre < lastnumber; incre ++)
        {
            string temp = base_string;
            temp[string_length-1] = (char)incre;
            toPrint.add(temp);
        }
        for(int i = 2; i <= base_string.length; i++ )
        {
            int currentnumber = Int16.Parse(base_string[base_string.length - i]);
            int number_limit = Int16.Parse(num_string[base_string.length -i]));
            if(currentnumber < number_limit)
            {
                currentnumber = currentnumber +1;
                base_string[base_string.length - i] = (char)currentnumber
                finished = false;
                break;
            }

            if(finished)
            {
                base_string[base_string.length - i] = 0
            }
        }

        if(finished)
        {
            running = false;
        }

    }
    string [] asd = toPrint.ToArray()
}

这是您要找的吗？如果没有，您能否提供更多详细信息，以便我获得更好的背景信息？