matlab - 我的 tic-tac-toe 程序在 matlab 中不起作用

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我在 matlab 中编写了一个井字棋游戏，但它不起作用:

%// 1) Commence the game, display empty board 

board=cell(3);

%// 2) Select which player is ?X? and ?O? (at random) 

playersymbols={'X','O'};
playersymbolindex=randperm(2);
for i=1:2
    player(i).symbol=playersymbols{playersymbolindex(i)};
end

winner=0;

while winner<1 
    %// 3) Request player1?s move

    player1move=input('Player 1, please enter your move: ');

    %// the input is something like [1 3] where the first number is the
    %// row number and the second number is column number so that [1 3] will
    %// put X in row 1, column 3.

    %// Redraw updated board. 
    board{player1move(1),player1move(2)}=player(1).symbol;
    board



    %// 5) Decision: has the game been won yet? If so, go to step 9).
    %//    If not, go to step 6). 

    %// The game is won when three respective X are placed in a horizontal,
    %// vertical, or diagonal row.

    if board{1,1}==board{1,2} & board {1,2}==board{1,3} | ...
       board{2,1}==board{2,2} & board{2,2}==board{2,3} | ...
       board{3,1}==board{3,2} & board{3,2}==board{3,3} | ...
       board{1,1}==board{2,1} & board{2,1}==board{3,1} | ...
       board{1,2}==board{2,2} & board{2,2}==board{3,2} | ...
       board{1,3}==board{2,3} & board{2,3}==board{3,3} | ...
       board{1,1}==board{2,2} & board{2,2}==board{3,3} | ...
       board{1,3}==board{2,2} & board{2,2}==board{3,1}

        %// 9) Display winner on the screen. 

        disp('Winner is player 1!')

        winner=1; 
    else

        %// 6) Request player2?s move 

        player2move=input('Player 2, please enter your move: ');

        %// 7) Input Player2?s move. Redraw updated board.

        board{player2move(1),player2move(2)}=player(2).symbol;
        board


        %// 8) Decision: has the game been won yet? If so, go to step 9). 
        %//    If not, go back to step 3). 

        if board{1,1}==board{1,2} & board {1,2}==board{1,3} | ...
           board{2,1}==board{2,2} & board{2,2}==board{2,3} | ...
           board{3,1}==board{3,2} & board{3,2}==board{3,3} | ...
           board{1,1}==board{2,1} & board{2,1}==board{3,1} | ...
           board{1,2}==board{2,2} & board{2,2}==board{3,2} | ...
           board{1,3}==board{2,3} & board{2,3}==board{3,3} | ...
           board{1,1}==board{2,2} & board{2,2}==board{3,3} | ...
           board{1,3}==board{2,2} & board{2,2}==board{3,1}

           %// 9) Display winner on the screen. 

           disp('Winner is player 2!')
           winner=1;
        end
    end
end

我非常努力地试图理解我做错了什么，但 4 小时后，我不知道我做错了什么。有人可以帮我吗？我做错了什么？

编辑: 玩家 1 没问题，所以问题出在玩家 2 身上。当玩家 2 获胜时，我的程序不会显示“玩家 2 赢得了比赛”，而是错误地要求玩家 1 接下来移动(当游戏已经完成时)。

Answer 1

我发现了问题。

当您将字符串与 == 进行比较时而不是 strcmp ，当存在空字符串时，比较返回 [] 。因此逻辑运算符 TRUE | []返回[]这是不正确的。

在您发布的示例中 ([1 1], [1 2], [2 1], [2 2], [1 3], [3 2]) if 的最后一行返回[]

board{1,3}==board{2,2} & board{2,2}==board{3,1}

看起来如果你用 && 替换你的逻辑运算符和||你可以解决这个问题。